Can electrogravimetry give total copper concentration and determine the concentration of specific species of either Cu(II) or Cu (I)? Why? And does it require a standard calibration curve? If not, how can the amount of analyte be determined? What about Polarography?
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Can electrogravimetry give total copper concentration and determine the concentration of specific species of either Cu(II) or Cu (I)? Why? And does it require a standard calibration curve? If not, how can the amount of analyte be determined?
What about Polarography?
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- If a second brass washer of 0.6003 grams had been dissolved in nitric acid, diluted to 50.00 mL and then its absorbance measured at 0.450, what would be the concentration of Cu(NO3)2 in the solution? What would be the mass percent of copper in the second brass washer? Use equation of the line as y = 3.1295 x + 0.0055.Determination of metals in soil by AAS Soil Mass of Soil ppm (mg/L) Concentration of Cu in soil Absorbance 1 1.0101g 0.6545 2 1.0064g 0.6203 3 1.0018g 0.5287 Show the calculation on how to calculate the ppm and the concentration of copper in the sample (soil). (The final volume is 200mL)Nick and Kel reacted 2.80g of NiCl2 x 6H20 with 7.00 ml of 4.00 M C2H8N2. They recovered 2.40g of product, [Ni(C2H8N2)3] Cl2. At the end, the filtrate was a dark blue solution. The litmus test on the filtrate solution left the red litmus paper unchanged in color. - NiCl2 x 6H2O + 3C2H8N2 yields [Ni(C2H8N2)3] Cl2(s) + 6H20 - Molor mass of NiCl2 x 6H20 is 237.69 g/mol - Molarity of C2H8N2 is 4.00 M - Molor mass of product,[Ni(C2H8N2)3] Cl2(s) is 309.90 g/mol based on the experiment described, what are answers for the question below the actual or experimenting yield is ________ the theoretical yeild is _____
- Nick and Kel reacted 2.80g of NiCl2 x 6H20 with 7.00 ml of 4.00 M C2H8N2. They recovered 2.40g of product, [Ni(C2H8N2)3] Cl2. At the end, the filtrate was a dark blue solution. The litmus test on the filtrate solution left the red litmus paper unchanged in color. - NiCl2 x 6H2O + 3C2H8N2 yields [Ni(C2H8N2)3] Cl2(s) + 6H20 - Molor mass of NiCl2 x 6H20 is 237.69 g/mol - Molarity of C2H8N2 is 4.00 M - Molor mass of product,[Ni(C2H8N2)3] Cl2(s) is 309.90 g/mol based on the experiment described, what are answers for the question below the actual or experimenting yield is __2.40g______ the theoretical yeild is __2.89g___ (can someone show me how to caluculate to get this answer?)Gold can be determined in solutions containing high concentrations of diverse ions by ICP-AES. Aliquots of 50.0 mL of the sample solution were transferred to each of four 100.0 mL volumetric flasks. A solution was prepared containing 10.0 mg/L Au in 20% H2SO4 and quantities of this solution were added to the sample solutions to give 0, 2.5, 5, and 10 mg/L added Au in each of the flasks. The solutions were made up to a total volume of 100.0 mL, mixed, and analysed by ICP-AES. The resulting data are presented in the following table. Added Au, mg/L Emission Intensity Count 12,568 19,324 26,622 40,021 0.0 2.5 5.0 10.0 Calculate the concentration of gold in the original sample.The iron content of a large lump of ore is determined by taking a single small sample, dissolving it in acid, and titrating with ceric sulphate after reduction of Fe (III) to Fe (II). What are the possible source of random and systematic errors?
- Which form if EDTA is used in any analytical experiment? Why?and l x + zakeAssignment/takeCovalentActivity.do?locator-assignment-take X A copy of your chemistry textbook is found to have a mass of 2.52 x 10³ grams. Using unit analysis, show what the mass of the copy of your chemistry textbook is in milligrams. Use one of the following to set up the conversion factor. 1 kg 1000 g 1000 mL-1 L 100 cm=1 m 1000 mg=1 g 1 mL=1 cm³ 1000 mm=1m 3 2.52 x 10³ g x 80 F3 E D Submit Answer C $ 4 888 F4 R F (number) (unit) [Review Topics] [References] Use the References to access important values if needed for this question. (number) (unit) % 5 V Retry Entire Group 8 more group attempts remaining Cengage Learning Cengage Technical Support 29 F5 T G A 6 B MacBook Air F6 mg Y H & 7 N 44 F7 U J * 00 8 DII F8 I M K ( 9 DD F9 O . { Previous [ 11 4G Next> Save and Exit 4)) F12 } * O 1 delete MIT ¡ ? SiliftThe concentration of Fe²+ in a sample is determined by measuring the absorbance of its complex with ferroxine. The sample, measured in a 1.00 cm cuvette, has an absorbance of 0.240. The reagent blank in the same cuvette has an absorbance of 0.039. What would be the absorbance reading for each of these two solutions if measured in a 7.00 cm cuvette? Asample= Areagent blank =
- A spectrophotometric method for the analysis of iron has a linear calibration curve for standards of 0.00, 5.00, 10.00, 15.00, and 20.00 ppm. An iron ore sample with an expected iron content of 40–60% w/w is to be analyzed by this method. An approximately 0.5-g sample is taken, dissolved in a minimum of concentrated HCl, and diluted to 1 L in a volumetric flask using distilled water. A 5.00-mL aliquot is removed with a pipet. To what volume (10, 25, 50, 100, 250, 500, or 1000 mL) should it be diluted to minimize the uncertainty in the analysis? Explain.Gold can be determined in solutions containing high concentrations of diverse ions by ICP. Aliquots of 50.0 mL of the sample solution were transferred to each of four 100.0 mL volumetric flasks. A solution was prepared containing 10.0 mg/L Au in 20% H2SO4, and quantities of this solutions were added to the sample solution to give 0, 2.5, 5 and 10 mg/L added Au in each of the flask. The solutions were made up to a total volume of 100.0 mL, mixed and analyzed by ICP. The resulting data are presented in the following table: Added Au (mg/L) Emission Intensity (Counts) 0.0 12568 2.5 19324 5.0 26622 10.0 40021 a) Attach an excel graph for the determination showing the X intercept. b) Calculate the concentration of gold in the sample, report with its uncertainty. c) The known concentration of gold in the sample is 8.51 mg/L. Test the hypothesis that your result is equal to this value at the 95% confidence level. lChemistry Explain why manganese which has an average minimum exploitable grade of 35% has a higher concentration factor compared to gold which has an average minimum exploitable grade of 0.0001%.