(-)-Cholesterol has a specific rotation of -32o. A mixture of (+)- and (-)-cholesterol was analyzed by polarimetry, and the observed rotation was 14o. What is the percent composition of the (+) isomer in this mixture?Assume 1 g of sample was dissolved in 1 mL water and the sample cell was 1 dm long.
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(-)-Cholesterol has a specific rotation of -32o. A mixture of (+)- and (-)-cholesterol was analyzed by polarimetry, and the observed rotation was 14o. What is the percent composition of the (+) isomer in this mixture?Assume 1 g of sample was dissolved in 1 mL water and the sample cell was 1 dm long.
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- 5. Solution A contains 9 g of pure (-)-fructose was diluted to 500 mL with water and placed in a polarimeter tube 20 cm long. The measured rotation was -3.31°. a. Calculate the specific rotation of the compound in the solution. b. If Solution A were mixed with 500 mL of a solution containing 2 g of racemic fructose (Solution B), what would be the optical purity (% enantiomeric excess) of the resulting fructose mixture?(+)-menthol has a specific rotation of +50°. A mixture of (+)-menthol and (-)-menthol in a certain synthetic sample was analyzed as follows. 6.972 g of sample was dissolved to make a 25 mL solution, and then placed in a 10 cm tube. The optical rotation of the solution was -10°. What is the enantiomeric excess of the mixture? Report your answer to the correct number of significant figures. % ee Which enantiomer (+ or -) corresponds to the major enantiomer present? )-menthol What are the percentages of each enantiomer in the mixture? Report your answer to the correct number of significant figures. % (+)-menthol % (-)-mentholThe specific rotation for D-glucose is 52.70⁰. In a mixture of D- and L-glucose, you measure an observed rotation that has a negative value. You calculate the % ee of the mixture to be 55%. What is the molecular composition of your mixture? (if you are lost here, watch the video, or look in your Technique Manual for guidance) 55% D, 45% L-glucose 45% D, 55% L-glucose O 77.5% D, 22.5% L-glucose 22.5% D, 77.5% L-glucose
- 0.5 g of optically-enriched (-)-mandelic acid was dissolved in 10 mL of absolute ethanol. Using a 1 dm polarimeter tube, the observed optical rotation was found to be -6.8°. What is the specific rotation?A 0.100 M solution of an enantiomerically pure chiral compound D has an observed rotation of +0.22" in a 1-dm sample container. The molar mass of the compound is 137.0g/mol. What is the specific rotation of D? What is the observed rotation of 100 mL of a solution that contains 0.01 mole of D and 0.005 mole of L? Assume a l-dm path length. observed rotation: 0.10 IncorrectThe following data was collected for this experiment: A sample of 0.8281 g of phenylsuccinic acid was dissolved in 10 mL of acetone. This sample gave a reading, aobs, of +10.278 deg on the polarimeter. A tube measuring 1 dm was used for the sample. What is the major enantiomer present in this sample? Calculate the concentration of the sample used in g/mL. Calculate the observed specific rotation [a]obs of the sample. Give your answer to 4 significant figures.
- When 0.018 g of cholesterol is dissolved in 1.00 mL of ether and placed in a sample cell 10.0 cm in length, the observed rotation at 20 degrees (Using the D line of sodium) is -0.0567 degrees. Calculate the specific rotation of cholesterol. specific rotation= [α] =Why is it necessary to resolve chiral pharmaceuticals (why cant we just use racemic versions)? What are the important criteria of a good resolving reagent? In particular why is (S)- methylbenzylamine a suitable resolving agent for ibuprofen4 What are enantiomers? What instrument can you use to distinguish the enantiomers? What is racemic mixture? What is enantiomeric excess (e.e)? 5 For a chiral compound with 2 chiral centers how many configurations (also called isomers in lose sense) are possible. Use 2¹ rule. 6 Pure (R)- lactic acid has rotation of + 12.31º. A mixture of lactic acid has a specific rotation of +2.71º. Determine the percent composition of two enantiomers (R) and (S) in the mixture.
- 7. A 0.5 gram sample of hoodia gordonii isolated from natural sources yields an observed rotation of -0.76° when dissolved in 20 mL of chloroform and placed in a 1-dm cell. Determine the specific rotation [α] of hoodia gordonii for: (a) the entities as defined above,(b) an increase in solute from 0.5g to 1.0 g;(c) an increase in solvent from 20 mL to 40 mL; and (d) an increase in path length from 1 dm to 2 dm. Does entities defined above refer to the picture since its a hoodia gordnii? I don't even know where to start with this oneA new chemical reaction produced a mixture of two enantiomers. When 9.0 g of this mixture was dissolved in 50.0 mL of CH2Cl2 in a sample cell 20 cm long, the optical rotation was found to be +18.0º. The known specific optical rotation of one of the enantiomers is –74.0. What was the percentage of the (+) and (–) enantiomers produced by the reactionViktor measures out 2.100 g of the ibuprofen from the bottle and dissolves it in 15.0 mL of ethanol. He transfers this solution to a 1.0 dm long tube and the polarimeter gives him a reading of +7.3416 deg for this sample. The literature specific rotation for ibuprofen is 57 deg. What is the observed specific rotation for this sample? What is the enantiomeric excess (EE) for this sample?