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- Differentiate. 5x - 9 -3 Зх + 1 g(x) = gʻ(x) = OA linear function y = f(x) has an x-intercept of -9 and a y-intercept of 2. The function undergoes the transformation y = f(x+h), h +0. Compared to the function y = f (x), the transformation of y = f (x +h) will have _ i to the x-intercept and ii _to the y-intercept. 9. The statement above is best completed by the answers in row: Row i ii a change a change no change no change no change a change a change no changeEvaluate the function f(x) = x - 5x+ 2 at the given values of the independent variable and simplify. а. f(-9) b. f(x + 5) c. f(- x)
- Find the point on the line y=−x−8y=-x-8 closest to the point (−6,−6)(-6,-6).The function giving the distance between the point and the line iss=s= (Enter a function of xx) The point on the line y=−x−8y=-x-8 closest to (−6,−6)(-6,-6) is (Enter the coordinates of the point. Be sure to include commas and parentheses as required.Differentiate. y =( x+1)/( x3 + x -2 )Simplify z3.(g*.z-7) (y I -2.y-5.2²
- find f(3,-7)Find the simplified difference quotient for each function listed. 46. f(x) — тх + b 47. f(x) = ax? + bx + c 48. f(x) = ax³ + bx² 49. f(x) = x* 50. f(x) = x3 51. fx) — ах5 + bxt 52. f(x) 53. f(x) 54. Below are the steps in the simplification of the difference quotient for f(x) = Vx (see Example 8). Provide a brief justification for each step. f(x + h) – f(x) Vx + h – Vx h Vx + h - Vx (Vx + h + Vx Vx +h + Vx. x + h + VxVx + h - VxVx + h – x h(Vx + h + Vx) b) x + h - x c) h(Vx + h + Vx) h d) h(Vx + h + Vx) 1 Vx + h + VxDifferentiate each function by applying chain rule. Match each item to a choice: y = x(x² + 3)² y = (4x – 10)4 - f (x) = (3x² – 2x + 1)® - Choices: (x² + 3)² + 4.x²(x² + .3) (36х — 12) (Зг? — 2лт + 1)5 2.x + 1)° - - 16(4x – 10)3 5x + 18x? + 9 - ::: ::