Compute the present value for the alternative below if the analysis period is 8 years: Alternative: • First cost: 5000 • Uniform annual benefit: 1800 • Useful life in years: 4 Answer:
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- For the cash flows shown, determine the incremental cash flow between machines B and A for (a) year 0, (b) in year 3, and (c) in year 6. Machine First Cost, $ АОС, $/year Salvage value, $ 3,000 Life, years B -15,000 -25,000 -1,600 -400 6,000 3 4 O (a) = -10000 (b) = -1800 (c) = 1200 %3D !3! O (a) = -10000 (b) = 13200 (c) = 4200 !3! %3! O (a) = -10000 (b) = 13200 (c) =6000 %3! %3D O (a) = -10000 (b) = 13200 (c) = 13200 %3DAs an engineer, you are responsible to find the best alternative that is economically best. The cash flows shown in the table and the MARR is 11 % per year. Then please answer the following questions. Cash Flow Project 01 Project 02 Project 03 First Cost, $ -90000 220000 230000 Annual Cost, $ Per Year -60000 -21000 -17000 Overhaul Every 10 Years, $ _ _ -60000 Salvage Value, $ 8000 29000 11000 Life, Years 3 10 a) Find the Aw for Project 01. b) calculate the AW for Project 02 c) Calculate Aw for Project 03. What is your decision?! Required information A company that manufactures magnetic flow meters expects to undertake a project that will have the cash flows estimated. First cost, $ Equipment replacement cost in year 2, $ Annual operating cost, $/year Salvage value, $ Life, years -740,000 -300,000 -790,000 250,000 4 At an interest rate of 10% per year, what is the equivalent annual cost of the project? Find the AW value using tabulated factors. The equivalent annual cost of the project is $- 1,007,097.68.
- Required information The TT Racing and Performance Motor Corporation wish to evaluate two alternative machines for NASCAR motor tune- ups. Machine First cost, $ Annual operating cost, $ per year Life, years Salvage value, $ -254,000 -40,000 The better alternative is machine S 3 20,400 Use the AW method at 9% per year to select the better alternative. The annual worth of machine R is $- S -360,500 -50,000 5 19,600 47694, and the annual worth of machine S is $- 10970A solid-waste recycling plant is considering two types of storage bins. Use ROR evaluation and an MARR of 46% per year to determine which should be selected. Storage Bin First Cost, $ AOC, $ per Year Salvage Value, $ Life, Years P -24,000 -4000 1800 3 Q -35,000 -2000 2600 6 Since A/* is (Click to select) MARR of 46%, (Click to select) should be selected.Buying Equipment 1 from XYZ company and company ABC will give the production similar productivity input of 400,000.00 per year. The equipment from company XYZ has a purchase price of 200,000.00, annual maintenance of 5,000.00, and production life of 10 years, while the equipment from company ABC has a purchase price of 100,000.00, annual maintenance of 2,000.00, and production life of 12. Using present worth method, what is the present values of their purchase profit? Use MARR of 20%
- Buying Equipment 1 from XYZ company and company ABC will give the production similar productivity input of 400,000.00 per year. The equipment from company XYZ has a purchase price of 200,000.00, annual maintenance of 5,000.00, and production life of 10 years, while the equipment from company ABC has a purchase price of 100,000.00, annual maintenance of 2,000.00, and production life of 12. Using present worth method, what is the total present worth of each alternatives? Use MARR of 20%Two alternatives are being considered for the upgrades to a detector at an X-ray synchrotron facility. Which alternative would be selected based the present worth, if the interest rate is 10% per year? Please note: The alternatives are mutually exclusive! Alternative A B First Cost, $ Operational & Maintenance Costs, $ -25,000 ||-10,000 Salvage Value, $ Life, years |-100,000|-140,000 20,000 30,000 4 12 Alternative A, PW= -$250,349 а. Alternative A, PW= -$355,931 Ob. Alternative B, PW = -$198,578 C. Alternative A, PW= -$120,968 Od.In comparing the machines on a present worth basis, the present worth of machine X, the cost of money is 10% per year, is closest to Machine X Machine Y Initial cost, $ -66,000 -46,000 Annual cost, $/year Salvage value, $ Life, years -10,000 -15,000 10,000 24,000 3. $-103,908 $-87,840 None of the answers S-65,270
- At i = 10% per year, a machine has a first cost of $8,000 and estimated operating costs and year-end salvage values as shown. The annual equivalent cost if you operate the machine for 3 years is closest to which value? Year 1 234N 5 Operating Cost, $ -1000 7000 -1200 5000 -1500 4200 -2000 3000 -3000 2000 Salvage Value, $Question 5: A metallurgical engineer is considering two materials for use in a space vehicle. All estimates are made. (a) Which should be selected on the basis of a present worth comparison at an interest rate of 12% per year? Vishes First cost, $ Maintenance cost, $ per year Salvage value, $ Life, years Material X Material Y -15,000 -35,000 -9,000 2,000 -7,000 20,000 5 5A construction firm needs a new small loader. It can be leased from the dealer for 3 years for $5500 per year including all maintenance, or it can be purchased for $27,000. The firm expects the loader to have a salvage value of $8500 after 8 years. The maintenance will be $650 the first year and then it will increase by $250 each year. The firm’s interest rate is 10% per year. Compare the EUACs for leasing and buying the loader.