Consider a vector ('L', 'M', 'M', 'L', 'H', 'M', 'H', 'H'), where H stands for ‘high’, L stands for ‘low’, and M for ‘medium’ in rstudio. a. Convert this vector into an unordered factor. b. Convert this vector into an ordered factor with Low < Medium < High.
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- Write a function linear_independence that takes a collection of vectors with integer entries (each written as a list), and returns True if this collection of vectors is linearly independent, and False otherwise. Examples: linear_independence([1,2]) should return True. linear_independence([1,3,7],[2,8,3],[7,8,1]) should returnTrue. linear_independence([1,3,7],[2,8,3],[7,8,1],[1,2,3]) should return False.The vector x ∈ R N has L different entries. For example, L = 4 for x = [3,4,4,5,3,1,5,3]T . One can express x as x = S u, where u ∈ R L satisfies (u)i < (u)j if i < j and S is a matrix that contains only zeros and ones. Write the function repeated_entries, which takes x as input and returns S and u.Assume that EMB(w) is the word embedding for a word, w, computed by some common technique for computing word embeddings (e.g., word2vec). Consider the vector obtained by the following vector arithmetic: EMB("Japan") + EMB("Paris") - EMB("Tokyo"). Other than the words that already related to this equation, what word's embedding would likely be close to the result? Briefly explain (in one sentence) your answer.
- Write a program that inputs a matrix and displays the trans- pose of that matrix. A transpose of a matrix is obtained by converting all the rows of a given matrix into columns and vice versa.For input vector x, write a function to check whether there exists exactly 4 elements in x which are divisible by 3.x²+3x+3 Q14) Plot the function f(x) = 0.8(x+1) for -4 ≤ x ≤ 3. Notice that the function has a vertical asymptote at x=-1. Plot the function by creating two vectors for the domain of x. The first vector (name it x1) includes elements from -4 to -1.1, and the second vector (name it x2) includes elements from -0.9 to 3. For each x vector create a y vector (mane them y1 and y2) with the corresponding values of y according to the function. To plot the function, make two curves in the same plot (yl vs. x1, and y2 vs. x2).
- My questions is in this example I read from my R textbook: test_function = function(x) {x[x<0] = -x[x<0]return(x)} It is designed to return a negative number for all values in a vector, such that is you pass -3, -2, 2, 3 in, as such: test_function(c(-3,-2,2,3) The out put would be 3 2 2 3 My question is can you explain to me the logic of how this works?Define a function ComputeNegations() that takes an input double vector parameter and an output vector parameter passed by reference. The function stores the negative of each input vector element to the output vector. Ex: If the input is: 3 -2.5 6.0 3.0 then the vector has 3 elements (-2.5, 6.0, 3.0) and the output is: 2.5 -6.0 -3.0 3 #include 4 using namespace std; 5 6 * Your code goes here */ 7 8 int main() { 9 int i; 10 11 12 13 14 15 16 17 18 19 20 vector inputVector; int size; double input; vector negated; cin >> size; for (i = 0; i > input; 1} inputVector.push_back(input);Perform the following vector multiplication of two vectors and find the y-component of the resulting vector, c. č = à xb ā = [ax ay az] b = [b, by b;] where ax = 5, ay = 5, az = 5 and by = 9, by = -7, b, = -8. %3D Your Answer:
- Create a factor vector from the values currently in vector x below x <-c("Low","Medium","High") X <- (x,order= =c("Low","Medium","High"))Write a user-defined function that determines the value that occurs most often in a set of data that is given in a two-dimensional matrix. For the func- tion name and arguments, use [v, q] =matrixmode (x). The input argu- ment x is a m×n matrix of any size with numerical values, and the output arguments v and q are the values that occur most often and the number of times they occur. If there are two, or more, values that occur most often than v is a vector with these values. Do not use the MATLAB built-in func- tion mode. Test the function three times. For input create a 5×6 matrix using the following command: x=randi (10,5,6).Q1. Design a generic matrix multiplier. Here ‘generic’ means the design should work for anymatrix multiplication X∙Y = Z, where the matrices X, Y, and Z are of sizes a×b, b×c, and a×crespectively. Now, pick a, b, c from the last three digits of your roll number. ( If any of the digitsis 0, take 3 instead of it; if two digits are 0s, then take 3 for the first 0, and 5 for the second 0)For Example, if the last three digits are 123 then a = 1, b = 2, and c = 3; if the last three digitsare 204 then a = 2, b = 3, c = 4; f the last three digits are 100 then a = 1, b = 3, c = 5.