Consider the equilibrium system described by the chemical reaction below. If 8.98 x 104 moles of KOH(aq), 8.98 x 104 moles of HCN(aq), and 0.0500 moles of KCN (aq) are present in a 1.00 L aqueous solution at equilibrium at 298 K, what is the value of K of the reaction at this temperature? KCN(aq) + H,O(I) = KOH(aq) + HCN(aq) [8.98 x 10¹] K = [0.0500] [1.80 x 10²] 1 [8.06 x 10¹'] = 1.80 x 10.² RESET 1.61 x 10-5

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Chapter12: Chemical Equilibrium
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Consider the equilibrium system described by the chemical reaction below. If
8.98 × 104 moles of KOH(aq), 8.98 × 104 moles of HCN(aq), and 0.0500 moles
of KCN(aq) are present in a 1.00 L aqueous solution at equilibrium at 298 K,
what is the value of K of the reaction at this temperature?
KCN(aq) + H,O(I) = KOH(aq) + HCN(aq)
[8.98 × 104]
K
||
[0.0500]
[1.80 x 10-²]
1
[8.06 x 10-7]
1.80 x 10-²
RESET
1.61 x 10-5
Transcribed Image Text:Consider the equilibrium system described by the chemical reaction below. If 8.98 × 104 moles of KOH(aq), 8.98 × 104 moles of HCN(aq), and 0.0500 moles of KCN(aq) are present in a 1.00 L aqueous solution at equilibrium at 298 K, what is the value of K of the reaction at this temperature? KCN(aq) + H,O(I) = KOH(aq) + HCN(aq) [8.98 × 104] K || [0.0500] [1.80 x 10-²] 1 [8.06 x 10-7] 1.80 x 10-² RESET 1.61 x 10-5
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