attached output onConsider the following code:found= Falsefailed Trueif failed == "false":print("T1")if found != failed:print("T2")if not found and failed:print("T3")if not failed:print("T4")if not failed or found:print("T5")The output of the code is:Drag and drop the correct answers in the corresponding boxes above:T2 T3 T5 T4 T1

Below I have provided a program for the given question. Also, I have attached a screenshot of the…

Consider the following code: found= False failed True if failed == "false": print("T1") if found != failed: print("T2") if not found and failed: print("13") if not failed: print("T4") if not failed or found: print("T5") The output of the code is: Drag and drop the correct answers in the corresponding boxes above: T2 T3 T5 T4 T1

Consider the following code: found= False failed True if failed == "false": print("T1") if found != failed: print("T2") if not found and failed: print("13") if not failed: print("T4") if not failed or found: print("T5") The output of the code is: Drag and drop the correct answers in the corresponding boxes above: T2 T3 T5 T4 T1

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Debugging: Find the error if there's any and rewrite
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Credit Card Number CheckThe last digit of a credit card number is the check digitwhich protects against transcription errors such as an error in a single digit or switching two digits. The following method is used to verify actual credit card numbers but, for simplicity, we will describe it for numbers with 8 digits instead of 16: Starting from the rightmost digit, form the sum of every other digit. For example, if the credit card number is 4358 9795, then you form the sum 5 + 7 + 8 + 3 = 23 . Double each of the digits that were not included in the preceding step. Add all digits of the resulting numbers . For example, with the number given above, doubling the digits. starting with the next-to-last one, yields 18 18 10 8. Adding all digits in these values yields 1 + 8 + 1 + 8 + 1 + 0 + 8 = 27 Add the sums of the two preceding steps . If the last digit of the result is 0, the number is valid . In our case , 23 + 27 = 50 , so the number is valid . Write a program that implements this…