Consider the following equilibrium reaction for hydrocyanic acid, HCN. HCN H+ + CN At 25°C the concentrations are found to be [HCN] = 0.0160 M and [H+] = [CN-] = 2.0 x 10-6 M. What is the value of the equilibrium constant at 25°C? (Show your work.)

General, Organic, and Biological Chemistry
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ISBN:9781285853918
Author:H. Stephen Stoker
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Chapter9: Chemical Reactions
Section: Chapter Questions
Problem 9.76EP: Calculate the value of the equilibrium constant for the reaction N2(g)+2O2(g)2NO2(g) if the...
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After solving this question, if an additional 0.01 moles of HCN are added to 1 Liter of this mixture, what will the new concentrations of each substance be?
Consider the following equilibrium reaction for hydrocyanic acid, HCN.
HCNH+ + CN
At 25°C the concentrations are found to be [HCN] = 0.0160 M and [H+] = [CN-] = 2.0 x 10-6 M. What is the value of the
equilibrium constant at 25°C? (Show your work.)
Transcribed Image Text:Consider the following equilibrium reaction for hydrocyanic acid, HCN. HCNH+ + CN At 25°C the concentrations are found to be [HCN] = 0.0160 M and [H+] = [CN-] = 2.0 x 10-6 M. What is the value of the equilibrium constant at 25°C? (Show your work.)
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