Construct the truth table and draw the logic circuit using the appropriate logic gates for each logic expression below: 1. Z = NOT(A AND B) 2. X = (A•B) + (A•C) + (A•B•C) 3. ZA AND (NOT B) 4. Z = A OR B AND A OR C 5. Z = (A OR NOT B) AND (NOT A OR B)
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- Part a Design a logic circuit using the truth table Inputs output shown. Use only basic logic gates (AND, OR, NOT). Also, the circuit should use the FEWEST number of gates and the FEWEST number of inputs to the gates. Fully label all the inputs and outputs. a b. 1 1 1 1 1. 1 1 Part b Implement a 3-input XOR gate using only a 4x1 multiplexer and an inverter. Also complete the truth table in your answer sheets with the correct labels and function solution. Fully label all inputs and outputs. Part c Design a full-adder using half-adders and A- additional logic using the half-adder shown here. Pi GiQ5// Design a combinational .logic circuit that has 4-inputs (A,B,C,D) and one-output (F), the output will be high "1" when the majority of inputs are high"1", and then simplify the output use POS expression in K-map and draw logic circuit.Task 4: Simplifying Boolean functions Simplify the following Boolean expression F (A, B, C) = (A+C") +C (C.A' + (B.A) +C Draw the simplified Boolean expression using EWB. Find out the truth table of the circuit.
- OY Identify the Boolean Expression for the above given Logic Circuit. O a. Y = (A+ B)O (AOC) b. None of these O c.Y = (AOB)O (A+C) O d.y = (A+ B)O (AOC)boolean expression: P = not((not(a.b) + c) + a.c) (c) Show that P (the Boolean expression above) is equivalent to the Boolean expression Q = a · b · not(c) and draw the corresponding circuit.Draw a logic circuit that performed by this logic expression: * Ā·(Ē + C) · Ď · E = Y
- Q1: Let F1 = AOB, F2=AB, F3= A+C, F4= F1+F2+ F3 Implement the above Boolean expression with logic circuit .. giving the truth table.Q4. Design the logic circuit corresponding to the truth table shown in table to the right. Test the resulting circuit using Logisim. Submit the circuit file. Q5. Find the simplified expressons for T1 & Tl and draw their logic circuits using Logisim. Q6. 0 0 0 0 1 в 0 0 1 1 0 0 For the Boolean function с 0 1 0 1 0 1 T₁ T₂ 0 1 1 0 0 0 0 0 0 0 1 1 1 F = xy'z + x'y'z + w'xy + wx'y + wxy 0 0 0 0 1 1 1 1 00-- C 0 0 1 1 0 1 1 0 0 1 1 1 1 1 0 1 0 1 00 1 (a) Obtain the truth table of F (b) Draw the logic diagram, using the original Boolean expression. (c) Use Boolean algebra to simplify the function to a minimum number of literals. Obtain the truth table of the function from the simplified expression and show that it is the same as the one in part (a). (d) (e) Draw the logic diagram from the simplified expression, and compare the total number of gates with the diagram of part (b).2. Consider the circuit below. a. Write the Boolean expression for output F in terms of A, B and C. b. Construct a truth table for the circuit with A as MSB and C as LSB. c. Write the Canonical SOP and POS forms for output F. A B C 3. Draw the logic circuit represented by the expression F(A, B) = AB using no more than 5 units of 2-input NAND gate and write the corresponding Boolean expression.
- 2. Write the Boolean expression of the given logic circuit as shown below. X. F =Create a non-abbreviated logic diagram for the following Boolean Expressions. You can use all gates. • a'b+ ab' ((ab)'(b'c) + a'b'c') (a +b)(a' + c)(b' + c') (a e b+b e d)Draw the logic circuit represented by the following expressions a. A + B(C' + B'(D + AC))