Coulomb's law for the magnitude of the force F between two particles with charges and separated by a distance d is |F| = K|QQ|¹||| 1 where K = 4760, and €0 = 8.854 × 10-¹² C²/(N·m²) 1 is the permittivity of free space. Consider two point charges located on the x axis: one charge, 91-19.0 nC, is located at ₁ = -1.720 m; the second charge, q2 = 34.0 nC, is at the origin (x = 0). Part A What is (Fnet 3)z, the x-component of the net force exerted by these two charges on a third charge q3 = 54.5 nC placed between 9₁ and 92 at 3-1.065 m ? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures. ► View Available Hint(s) - ΑΣΦ 6 (Fnet 3)2 = 0.691 10 ● -26 ? N

Physics for Scientists and Engineers: Foundations and Connections
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Chapter23: Electric Forces
Section: Chapter Questions
Problem 29PQ: Two particles with charges q1 and q2 are separated by a distance d, and each exerts an electric...
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Coulomb's law for the magnitude of the force F between two
particles with charges and Q' separated by a distance d is
where K =
1
4περ
is the permittivity of free space.
J
= K
· |QQ'|
d²
and €0 =
"
¹² C²/(N·m²)
8.854 × 10-12
Consider two point charges located on the x axis: one charge,
91 = -19.0 nC, is located at x₁ = -1.720 m; the second
charge, q2 = 34.0 nC, is at the origin (x = 0).
Part A
What is (Fnet 3) x, the x-component of the net force exerted by these two charges on a third charge q3 = 54.5 nC placed between 9₁ and 92 at
x3 = -1.065 m ?
Your answer may be positive or negative, depending on the direction of the force.
Express your answer numerically in newtons to three significant figures.
► View Available Hint(s)
呃
ΑΣΦ
(Fnet 3)2 = 0.691 10
- 26
?
N
Transcribed Image Text:Coulomb's law for the magnitude of the force F between two particles with charges and Q' separated by a distance d is where K = 1 4περ is the permittivity of free space. J = K · |QQ'| d² and €0 = " ¹² C²/(N·m²) 8.854 × 10-12 Consider two point charges located on the x axis: one charge, 91 = -19.0 nC, is located at x₁ = -1.720 m; the second charge, q2 = 34.0 nC, is at the origin (x = 0). Part A What is (Fnet 3) x, the x-component of the net force exerted by these two charges on a third charge q3 = 54.5 nC placed between 9₁ and 92 at x3 = -1.065 m ? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures. ► View Available Hint(s) 呃 ΑΣΦ (Fnet 3)2 = 0.691 10 - 26 ? N
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