Describe the lime soda process for removing the hardness of water. Calculate the amount of lime and soda required for treatment of 10,000 liters of water containing the following salts in ppm. Al2 (SO4 ) 3 = 34.2 HCl = 7.3 MgCl2 = 19.0 NaCl= 58.5
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Describe the lime soda process for removing the hardness of water. Calculate the amount
of lime and soda required for treatment of 10,000 liters of water containing the following
salts in ppm.
Al2
(SO4
)
3 = 34.2 HCl = 7.3
MgCl2
= 19.0 NaCl= 58.5
Step by step
Solved in 2 steps
- Ca+2 = 36.8mg/L Mg+2 = 2.9mg/L HCO3 = 98mg/L pH = 7.53 Temp = 9C Calculate the following: a. Hardness in units of mg/L as CaCO3 b. Ionic strength (be sure to include H++ and OH--) c. PCO2 in equilibrium with the sample d. Saturation index with respect to calcite (SIC) e. Saturation index with respect to dolomite (SID)A water with low alkalinity of 15 mg/L as CaCO3 will be treated with the ferrous sulphate-lime coagulation. FeSO4 dosage is 18 mg/L. (CaCO3 = 100 g/mol, Ca(HCO3)2 = 162 g/mol, Ca(OH)2 = 74 g/mol, FeSO4.7H₂O = 278 g/mol, Fe(OH)2 = 90 g/mol). a. Determine the lime dosage needed to react with the ferrous sulphate for sweep coagulation. b. If dissolved oxygen (DO) concentration is 5 mg/L before coagulation, what is concentration of DO after coagulation?d) Calculate total hardness in ppm of a solution of both 55 mg/L Al2(SO4)3 and 45 mg/L Mg(NO3)2.
- 1. Which of the following is a weak acid? O H2SO4 O H2CO3 О но O HBrA 1g granular powder have the following data below, compute for the following: Volume of the solid alone = 1 cm3/g Volume of intraparticle pores = 0.2 cm3/2g Volume of spaces between particle = 3.2 cm3/g Volume after tapping = 2.4 cm3/2g Note: Answer should be in three decimal places A) Specific volume = ? cm3/g B) Specific granule volume = ? cm3/g C) Specific bulk volume = ? cm3/g D) Total porosity = ? E) Interspace porosity = ? F) Intraparticle porosity = ? G) Hausner ratio = ? H) Carr's compressibility index = ?Which of the following is/are correct: 1. X, =+X 2. X- BOD 3. BOD; = BOD 4. BOD, = !! where X and Xy are the total and the volatile solids, respectively, in the bioreactor, fo is the biodegradable fraction in the solids, Xey is the volatile solids in the effluent, BOD5 and BOD, are the 5-day and the ultimate biochemical oxygen demand, respectively, frelates BOD5 to BOD, and is less than 1. O 2 and 4 O 2 only O 1 and 3 O 2 and 3
- Please choose the correct answer for each question: 1. Activity of a gas in equilibrium with solution is ______? A. its partial pressure; B.1.0; C. its molar concentration; D. 0.0 2. During a sorption procedure, the substance transferred from the gas or liquid phase to the solid phase is called ______ A. sorbent; B. sorbate; C. partition; D. none of the above 3. When a chemical has a lower KOW, it is more ______ A. hydrophobic; B. hydrophilic; C. more absorbable; D. less absorbable 4. _____ occurs on the adsorbent surface A. Adsorption; B. Sorption; C. Absorption; D. Adsorption and absorption 5. _____ addresses the change in the amount of a substance of interest with time. A. The equilibrium approach; B. The kinetic approach; C. Henry’s Law; D. Freudlich isotherm equation6. The mineral analysis below was reported for a water sample. 6.0 Bicarbonate 120 as CaCO3 Ca2+ 50.0 SO?- 94.0 Mg* 20.0 pH 7.3 Na* 5.0 Note: All reported as "mg/L as the ion" unless stated otherwise. e. Draw a bar chart that includes all the ions listed above. f. What is the total hardness of the water in mg/L as CaCO3? g. What is the carbonate hardness of the water in mg/L as CaCO;? h. What is the non-carbonate hardness of the water in mg/L as CaCO3? How would you characterize this water (very soft, moderately hard, etc.)? Explain your i. answer.True or False: As the cations are removed from the soil colloids, they are replaced with acid-forming hydrogen and aluminum. Select one: O True O False
- A commercial screen cloth of market grade is used to separate different fractions of 300 m³/hr of crystals obtained from crystallization via nucleation process in a cylindrical vessel of 3 m height and 9.25 m OD of thickness 3.6 cm. The properties of the slurry are: M, = 220 g/L; p = 1.26 g/mL; P = k, = 0.97 Mesh Sizes wt % -7 mesh +9 mesh 1.68 -9 mesh +12 mesh 2.31 -12 mesh +14 mesh 2.12 -14 mesh +18 mesh 13.90 -18 mesh +24 mesh 32.89 -24 mesh +40 mesh 45.78 -40 mesh Find: Kinetic equation b. Dominant particle c. What is the cumulative weight fraction at 700 microns? а.:Hardness of Gypsum is more than hardness of Diamond O Talk O Calcite O :The ratio of volume of voids to volume of solids is Porosity O void ratio O Density OA commercial screen cloth of market grade is used to separate different fractions of 300 m3/hr of crystals obtained from crystallization via nucleation process in a cylindrical vessel of 3 m height and 9.25 m OD of thickness 3.6 cm. The properties of the slurry are: MT = 220 g/L; ρ = 1.26 g/mL; φ = kv = 0.97 Mesh Sizes wt % -7 mesh +9 mesh 1.68 -9 mesh +12 mesh 2.31 -12 mesh +14 mesh 2.12 -14 mesh +18 mesh 13.90 -18 mesh +24 mesh 32.89 -24 mesh +40 mesh 45.78 -40 mesh Find:a. Kinetic equationb. Dominant particlec. What is the cumulative weight fraction at 700 microns?