Determine the force in member BE of the loaded truss. Enter a positive number if in tension, negative if in compression. 11' B 14' 15° 15° F E 11' 15° 1.0 L 1.7L 15° 45° A Answer: BE = i !L 45° D

Determine the forces in members BC and CG. The forces are positive if in tension, negative if in compression. B 12' C 12' D 11' A 12' F 62° E 11 kips Answers: BC = i kips CG = kips

MH Determine the resultant force at pins A, B, and C on the three-member frame. 2m- A, =61.88 N A, = 569.06 N B = 338.12 N %3D N 008 Fc = 572 N FA = 572 N FB = 478 N C. %3D B, = 338.12 N %3D w/N 007 C, = 461.88 N %3D C, = -338.12 N 2m .09 A.W. of force

F1 d F2 E F3 a= 2.9m, b = 2.2m, c = 4.5m, d= 1.2m F=120N, F,= 2400N, 0, = 35°, F;= 500N. For the truss as shown and the loading indicated. 1. Use the method of joints to find the forces in AB and AG. Show the free body diagram for the joint: Olncluded in manual solution ONot made The force in member AB is: N (Tension:+, Compression: -1 The force in member AG is: N [Tension:+, Compression: -) 2. Find the force in members BC, BE, EF using the method of section. Show the free body diagram with required dimensioris and inclinations: Olncluded in manual solution ONot made The force in member EF: N [Tension:+, Compression: -] The force in member BC: N [Tension:+, Compression: -) The force in member BE: N (Tension:+, Compression: -] (Answer upto 1 decimal place for all values)