determine the maximum load Pu that the system below can carry.
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- Select all zero-force members in the truss shown below. Check the box for zero- force members 3m 12 m, 8 @ 1.5 m O DE LK EP OHF O BC O BM O EF O OM O CD O BN LO O DK FI O co O O O O O O 0 0 O 0The truss below is pin connected at A and E, and is acted on by the forces shown. E A D B Identify all of the ZERO-FORCE MEMBERS by checking the boxes below (if there are none, leave all boxes unchecked): BF AF BC BH CD EG -GH AB CH DG DH DE -FH2. Member BC in the truss below is a 300 mm wide, 10 mm thick steel plate attached to two other 12 mm plates at Joint C by three 24 mm diameter A325N bolts. The plate is A50. Determine the safe load Pu using ASD that the truss can resist according to the capacity of the connection. LS 15 WR + 14 DATE ON ON Mmm 70 m 40 mm
- Question 1 Check that the medium-term load of 38 kN applied to the spaced column shown in below complies with the design requirements of BS 5268-2. The column consists of two 38 x 150 C22 timbers 76 mm apart. All joints are glued and intermediate packs are 250 mm long. suitable connection #### x ->89² 6:38. Y T -end blocking AP 100 intermediate blocking L₂ 1₁ x W L W EFH 400 m 38kN medium term load -ICHICHID -200 600 600 600 600 600 600 200 38kN medium term loadQuestion 2 of 5 Using LRFD and A-50 steel, determine the maximum load Pu that the system below can carry. Assume welded connections at the joints. W8X10 5m 2m W8X15 Pu 4m CS Scanned with CamScannerM3 HW 4 4. Six rivets are used in the connection shown in the REVISED PROBLEM: figure. If both P= 50 kN, what is the minimum diameter P- 50 rivet is necessary so as not to exceed the 70MPA allow shearing stress? What thickness of plate is required so as not to exceed a bearing stress of 140 MPa? 80 mm 80 mm Pe so 100 mm
- Using LRFD and A-50 steel, determine the maximum load Pu that the system below can carry. Assume welded connections at the joints. W8 X 1B W8X15 4m PaA tension connection consists of A36 steel double angles (two L4x4x1/4 shapes, or 2L4x4x1/4) fastened to a 4x10 No. 2 Red Oak member with a single row of four 0.875 inch A307 bolts. The connection is subjected to normal temperatures but wet in-service conditions. Assume the group action factor is C,=0.95 and the geometry factor is Ca=1. The controlling ASD load combination is D+ L where L is from occupancy. Elevation Cross Section L4x4x1/4 L4x4x1/4 Pa Р. 2L4x4x1/4 4х10 4x10 Plan L4x4x1/4 Pa/2 Pa 4x10 L4x4x1/4 Pa/2 • Determine the load, Pa, that the connection can support based on tension strength of the 4x10. Pa=. lb • Determine the load, Pa, that the connection can support based on gross tension yield of the double angles. The ASD design strength for gross tension yield is F,A,/1.67 where F=36 ksi, A,=1.93 in² for each L4x4x1/4. Pa=. lbSelect all zero-force members in the truss shown below. Check the box for zero- force members 3 m 3 m 12 m, 8 @ 1.5 m DE O LK ЕР O HF O BC BM EF OM CD BN LO O DK FI O co
- 6. Member BC in the truss below is a 300 mm wide, 10 mm thick steel plate attached to two other 12 mm plates at Joint C by three 24mmp A490N bolts. The plate is A36. Determine the safe load Pu using LRFD that the truss can resist according to the capacity of the connection. 15 15 с 1.5 3P. + D 1.5 80 mm 70 mm 70 mm 80 mm Fac 7. Repeat Problem 6 using 30mm A325-N bolts and A-50 steel. Use ASD. 50 mm Fac10/10 find the tensile stress in upper plate in section 3-3 1 80 kN 80 kN 8-bolt DIA. 10 MM 80 kN 80 kN 8-bolt DIA. 10 MM ww 8 300 mm (2) -O- O 3)1- The bolted type connection will be used to assemble the given steel members. Determine the safe load that a single turned bolt can carry. Consider only the effect of shear stresses. (St-37, H) t= 20 # ##* JL 90.90.9 40 50 315 9,96 t 9,04 t 9,40 t 9,70 t