Differential Equations – Find the actual solution: 2+½ − 2t − [2 − ln(t² + 1)] y' = 0 t²+1 ; y (5) = 0

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Q: Differential 2ty t²+1 Equations - Find the actual solution: y' = 0, - 2t [2ln(t² + 1)] y (5) = 0

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