In dogs, a dominant gene (I) determines white coat, and a recessive gene (i) gives colored coat. In the presence of ii the coat color is black due to the dominant gene B, or brown due to the recessive gene b. Two dogs both having the Bbli genotype were mated. Answer the following questions and show complete solutions to support your answers. Use the branching method whenever applicable. a. What is the phenotypic ratio of the offspring? b. What type of gene interaction is exhibited by the coat color in dogs? c. What would be the probability of getting dogs that are pure-breeding for a black coat color?

In dogs, a dominant gene (I) determines white coat, and a recessive gene (i) gives colored coat. In the presence of ii the coat color is black due to the dominant gene B, or brown due to the recessive gene b. Two dogs both having the Bbli genotype were mated. Answer the following questions and show complete solutions to support your answers. Use the branching method whenever applicable. a. What is the phenotypic ratio of the offspring? b. What type of gene interaction is exhibited by the coat color in dogs? c. What would be the probability of getting dogs that are pure-breeding for a black coat color?

Biology (MindTap Course List)

11th Edition

ISBN:9781337392938

Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg

Publisher:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg

Chapter11: The Basic Principles Of Heredity

Section: Chapter Questions

Problem 2TYU: The F1 flies described in question 1 were mated with brown-eyed flies from a true-breeding line....

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In dogs, a dominant gene (1) determines white coat, and a recessive gene (i) gives colored coat. In the presence of ii the coat color is black due to the dominant gene B, or brown due to the recessive gene b. Two dogs both having the Bbli genotype were mated. Answer the following questions and show complete solutions to support your answers. Use the branching method whenever applicable. What is the phenotypic ratio of the offspring? What type of gene interaction is exhibited by the coat color in dogs? What would be the probability of getting dogs that are pure-breeding for a black coat color? 3. a. b. C.
Answer the following with a short solution if needed: a. The gametes of a worm's genotype SsYy should produce what genotypes? b. A genetic cross between two F1-hybrid rose plants having yellow petals will yield what percent green-petal plants in the F2 generation? Yellow petals are dominant to green. c. Brown fur is dominant over light-colored fur. What is the phenotype of the resulting offspring if you cross a heterozygous brown fur and a light-colored fur?
In mice, there is an allele that in the heterozygous condition, produces mice with yellow coats. Mice that are homozygous recessive for the allele have white-color coats. Homozygous dominant mice abort early or are born stillborn. If a yellow male is mated to female yellow mouse, what is the phenotypic ratio you would expect among the 15 living offspring? (Show your work below.)
The American Curl is a breed of cat that has curly ears. The allele for the curly ears is dominant (E). Suppose a cat with the heterozygous genotype is bred to a female cat with the homozygous recessive genotype. Fill out a Punnett Square and answer the following questions. What is the phenotypic ratio of this punnett square? If this cross produces six kittens, how many of them will have curly ears? ________
In cats, the allele for black fur (B) is dominant over the allele for brown fur (b). A heterozygous female cat mated with a homozygous recessive male cat.a. What is the genotype of the female cat?b. What is the phenotype of the female cat?e. Draw a Punnett square to show what kinds of kittens these two cats could make. What fraction of the kittens would you expect to have each genotype?
Hemophilia is a disease caused by a gene found on the X chromosome. Therefore, it is referred to as a sex-linked disease. The recessive allele causes the disease. A man with hemophilia (xhy) marries a woman who is homozygous dominant (XHXH. A. Illustrate using a Punnett square the probability that their children will have the disease. B. Will any of their children have the disease? C. Predict the probabilities of their children having the disease.
In certain species of flies, eye color is controlled by sim-·ple dominance by a single pair of alleles. A red-eyed fly was crossed with a white-eyed fly, both of whose parents had white eyes. All of their offspring (both female and male) had red eyes.a. Which is dominant, the allele for red eyesor the allele for white eyes?b. What is the genotype of the white-eyed parents?c. If the white-eyed parent was mated with one of the red-eyed offspring, what phenotypic ratio wouldyou expect regarding eye color?
In rabbits, black hair depends on a dominant allele, B, and brown hair on a recessive allele, b. short hair is due to a dominant allele, S, and long hair to a recessive allele, s. If a true-breeding black short-haired male is mated with a brown long-haired female, describe their offspring. What will be the genotypes of the offspring? If two of these f1 rabbits are mated, what phenotypes would you expect among their offspring? In what proportions?
A heterozygous individual is crossed with a homozygous recessive individual. a. Draw a Punnett square to represent this cross. b. What is the probability that an offspring will have a homozygous genotype? c. What is the probability that an offspring will have a dominant phenotype? d. What is the probability that three offspring will be produced that all carry the recessive allele but do not express the recessive phenotype?
A homozygous red pigmented female beetle (bb) is bred with a black pigmented male of unknown genotype. It’s unknown if the male homozygous dominant (BB) or heterozygous (Bb) for the pigment trait. The color of their offspring will help identify the genotype of the male. What do you call this method used to determine the genotype of the male beetle? Explain your answer by using Punnett square to show possible offspring genotypes.
Black eye (B) is dominant over brown eye (b). A man that is a homozygous dominant black-eyed marries a woman that is a heterozygous black-eyed. The offspring resulted to 50% homozygous black and 50% heterozygous black. If one of their heterozygous children marries another heterozygous partner. Regardless of its gender, what are the genotypes of their children? a. 25% BB, 50% Bb, 25% bb b. 50% BB, 25% Bb, 25% bb c. 25% BB, 25% Bb, 50% bb d. 0% BB, 75% Bb, 25% bb In Law of Codominance, a pure line dominant trait crossed with a recessive trait will result to the appearance of both dominant and recessive trait in the offspring. What is the percentage of having a red-haired offspring if the parental genotype is both a heterozygous roan haired? Red hair is a dominant trait and white hair is a recessive trait. a. 100% b. 75% c. 50% d. 25% e. 0%
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