Examine the following reaction. 3 CO 2 (g)+2 Fe(s) 5 Fe20 3 (s)+3 CO(g) What is the equilibrium expression for the reaction?

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ChapterU6: Showtime: Reversible Reactions And Chemical Equilibrium
SectionU6.2: How Backward: Reversible Reactions
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Examine the following reaction.
3 CO 2 (g)+ 2 Fe(s) 5 Fe203(s) + 3 CO(g)
What is the equilibrium expression for the reaction?
O Kc = [CO2]³ /[CO]3
O Kc = [Fe2O3] / [Fe]
O K = [COJ³ /[CO2]³
O Kc = [Fe] / [Fe2O3]
O Kc = [CO]/[CO2]
O Kc = [Fe2O3] [CO]³ / ([Fe]² [CO2]³)
O Kc = [CO2]/[CO]
O Kc = [Fe] [CO2] / ([Fe2O3] [CO])
O Kc = [Fe]? [CO2]³/ ([Fe,O3] [CO]³)
O Kc = [Fe2O3] [CO]/ ([Fe] [CO2])
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Transcribed Image Text:Examine the following reaction. 3 CO 2 (g)+ 2 Fe(s) 5 Fe203(s) + 3 CO(g) What is the equilibrium expression for the reaction? O Kc = [CO2]³ /[CO]3 O Kc = [Fe2O3] / [Fe] O K = [COJ³ /[CO2]³ O Kc = [Fe] / [Fe2O3] O Kc = [CO]/[CO2] O Kc = [Fe2O3] [CO]³ / ([Fe]² [CO2]³) O Kc = [CO2]/[CO] O Kc = [Fe] [CO2] / ([Fe2O3] [CO]) O Kc = [Fe]? [CO2]³/ ([Fe,O3] [CO]³) O Kc = [Fe2O3] [CO]/ ([Fe] [CO2]) %3D %3D %3D %3D
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