Examine the following reaction. 4 Al 203 (s) + 3 CI (aq) = 8 AI( s) +3 CIO 4 (aq) What is the equilibrium expression for the reaction? O K = [Al2O3]/ [AI] O K = [CI]/[CIO4'] O K = [AI]® [CIO4 / ([Al,Og]* [CI]°) OK = [CI']3 /[CIO 4 13 O K = [CIO4]³/[CI]3 O K = [CIO4]/[CIr] O K = [Al2O3]* [CI]/ ([AI]® [CIO419) O K = [Al] [CIO4]/ ([Al203] [CI]) O K = [AI]/[Al203] O K = [Al2O3][CI]/ ([AI] [CIO4"]) %3D %3D %3D %3D %3D

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