Example 5: Determine the sequence components if Va = 100 <30° V; <150° v & Vb 100 Vc = 100 <-90° v. Solution: Va0 = 1/3(Va + Vb + Vc) Val = 1/3(Va + a Vb + a2Vc) OV Va2 = 1/3(Va + a2 Vb + a Vc) = 100<30° v =0 V %3D %3D Observation: If the phasors are balanced, two sequence components will be zero.

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter6: Power Flows
Section: Chapter Questions
Problem 6.40P
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Answer example number 5
Thursday, March 24, 2022 11:13 AM
Example 4: Determine the sequence components if Ia =10<60° A; Ib =10<-60° A; Ic =
10 <180° A.
Solution:
Ta0 = 1/3(Ia + Ib+ Ic)
Ial = 1/3(Ia + a Ib + a2Ic)
Ia2 = 1/3(Ia + a2 Ib + a Ic) = 0 A
=0 A
= 10<60° A
%3D
%3D
Observation: If the phasors are balanced, two sequence components will be zero.
Example 5: Determine the sequence components if Va = 100 <30° v;
<150° v & Vc = 100 <-90° V.
Vb = 100
%3D
Solution:
Va0 = 1/3(Va + Vb + Vc)
Val = 1/3(Va + a Vb + a2Vc) = 0 V
Va2 = 1/3(Va + a2 Vb + a Vc) = 100<30° v
=0 V
%3D
Observation: If the phasors are balanced, two sequence components will be zero.
Transcribed Image Text:Thursday, March 24, 2022 11:13 AM Example 4: Determine the sequence components if Ia =10<60° A; Ib =10<-60° A; Ic = 10 <180° A. Solution: Ta0 = 1/3(Ia + Ib+ Ic) Ial = 1/3(Ia + a Ib + a2Ic) Ia2 = 1/3(Ia + a2 Ib + a Ic) = 0 A =0 A = 10<60° A %3D %3D Observation: If the phasors are balanced, two sequence components will be zero. Example 5: Determine the sequence components if Va = 100 <30° v; <150° v & Vc = 100 <-90° V. Vb = 100 %3D Solution: Va0 = 1/3(Va + Vb + Vc) Val = 1/3(Va + a Vb + a2Vc) = 0 V Va2 = 1/3(Va + a2 Vb + a Vc) = 100<30° v =0 V %3D Observation: If the phasors are balanced, two sequence components will be zero.
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