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Example / What volume of 0.40 M Ba(OH)2 must be added to 50 mL of 0.30 M NAOH to give a solution 0.50 M in OH. Solution: Let x = mL Ba (OH)2 and the final volume is (50+x) mL mmole OH- = mmole Na0H + 2 x mmol Ba(OH)2 %3D 0.5M x (50 + x)mL = 0.30 M x 50 mL + 2 x (0.40MX (x) mL) x = 33 mL Ba(0H)2

Example / What volume of 0.40 M Ba(OH)2 must be added to 50 mL of 0.30 M NAOH to give a solution 0.50 M in OH. Solution: Let x = mL Ba (OH)2 and the final volume is (50+x) mL mmole OH- = mmole Na0H + 2 x mmol Ba(OH)2 %3D 0.5M x (50 + x)mL = 0.30 M x 50 mL + 2 x (0.40MX (x) mL) x = 33 mL Ba(0H)2

Introductory Chemistry For Today
Introductory Chemistry For Today
8th Edition
ISBN:9781285644561
Author:Seager
Publisher:Seager
Chapter7: Solutions And Colloids
Section: Chapter Questions
Problem 7.107E
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Example / What volume of 0.40 M Ba(OH)2 must be added to 50 mL of 0.30 M NaOH to give a solution 0.50 M in OH. Solution: Let x= mL Ba (OH)2 and the final volume is (50+x) mL mmole OH- = mmole NaOH +2 x mmol Ba(OH)2 0.5 M x (50 + x)mL 0.30 M x 50 mL + 2 x (0.40 M x (x) mL) x = 33 mL Ba(0H)2 Example / Prepare 500 mL of 0.010 M solution of Na from solid Na,CO3. /-
Transcribed Image Text:Example / What volume of 0.40 M Ba(OH)2 must be added to 50 mL of 0.30 M NaOH to give a solution 0.50 M in OH. Solution: Let x= mL Ba (OH)2 and the final volume is (50+x) mL mmole OH- = mmole NaOH +2 x mmol Ba(OH)2 0.5 M x (50 + x)mL 0.30 M x 50 mL + 2 x (0.40 M x (x) mL) x = 33 mL Ba(0H)2 Example / Prepare 500 mL of 0.010 M solution of Na from solid Na,CO3. /-
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