EXERCISE 2: Calculate the pH of a 0.50 M NH3 at 25°C. At 25°C, the base dissociation constant (Kb) of ammonia (NH3 ) is 1.8 × 10-5. Complete the ICE Table below: + Hydrolysis Equation NH4+ (aq) OH (aq) NH3(aq) + H₂O(l) INITIAL 0.50 0 (Analytical molarity) CHANGE -X +X EQUILIBRIUM (6 pts) [NH3] = [NHA] = [OH-] = Write the equilibrium expression for the base dissociation constant, K, and substitute the mathematical equation containing the variable x into the equilibrium expression. Then calculate the value of [OH-] and pH of the solution. Show your complete solution. 0 +X

General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter15: Acids And Bases
Section15.8: The Ph Of A Solution
Problem 15.10E: A 0.010 M solution of ammonia, NH3, has a pH of 10.6 at 25C. What is the concentration of hydroxide...
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EXERCISE 2: Calculate the pH of a 0.50 M NH3 at 25°C.
At 25°C, the base dissociation constant (Kb) of ammonia (NH3 ) is 1.8 × 10-5.
Complete the ICE Table below:
+
NH4+ (aq)
OH-(aq)
Hydrolysis Equation
NH3(aq) + H₂O(l)
INITIAL
0.50
0
(Analytical molarity)
CHANGE
-X
+X
EQUILIBRIUM
(6 pts)
[NH3]
[NH4*]
=
[OH-] =
Write the equilibrium expression for the base dissociation constant, K, and substitute the
mathematical equation containing the variable x into the equilibrium expression.
Then calculate the value of [OH-] and pH of the solution. Show your complete solution.
0
+X
Transcribed Image Text:EXERCISE 2: Calculate the pH of a 0.50 M NH3 at 25°C. At 25°C, the base dissociation constant (Kb) of ammonia (NH3 ) is 1.8 × 10-5. Complete the ICE Table below: + NH4+ (aq) OH-(aq) Hydrolysis Equation NH3(aq) + H₂O(l) INITIAL 0.50 0 (Analytical molarity) CHANGE -X +X EQUILIBRIUM (6 pts) [NH3] [NH4*] = [OH-] = Write the equilibrium expression for the base dissociation constant, K, and substitute the mathematical equation containing the variable x into the equilibrium expression. Then calculate the value of [OH-] and pH of the solution. Show your complete solution. 0 +X
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