Explain the order of chemical shifts of the carbon atoms in the 13C spectra of cyclohexanone (fig 22.6 ) and adipic acid (fig .22.9) attached below .
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- Draw the structure of the compound identified by the simulated 'H NMR and ¹3C NMR spectra. The molecular formula of the compound is C₁0H₁2O. (Blue numbers next to the lines in the 'H NMR spectra indicate the integration values.) ¹H NMR 1H 2H 2H 2H 2H 3H IT 111 10 8 6 8 (ppm) 13C NMR III. 220 200 180 160 140 60 40 20 100 8 (ppm) Deduce the structure from the spectra. Select Draw More CHO 2 Ć Rings 120 80 Erase Q 2 QHow could 1H NMR spectroscopy be used to distinguish among isomersA, B, and C?If the molecule giving the ¹H NMR spectrum shown below has a total of 10 protons, how many protons are represented by peak II? 4 PPM
- Draw the structure of the compound identified by the simulated 'H NMR and C NMR spectra. The molecular formula of the compound is C,0H,O. 12 (Blue numbers next to the lines in the 'H NMR spectra indicate the integration values.) H NMR 1H 2H 2H 2H 2H|| 3H 10 8. 4 (dd) g 13C NMR 220 200 180 160 140 120 100 80 60 40 20 8 (ppm) Deduce the structure from the spectra. Select Draw Rings More EraseDraw out the structure: The Key signals for IR are = 3090, 2800-3000,1700,1455,1560,1598,1110,1290 cm^-1. MS is = M+ 150,m/z121,105,77. 1H NMR is=7.5 –7.9 m,4.1 q,1.2 t.; 13C NMR: 14.4,60.8,128.4,129.7,131,133,167ppmI have an NMR spectrum. There are 5 peaks. There is a doublet at 9.6 ppm (integrates to 2H) where aldehydes usually arise, don't know why there is a doublet. There is another doublet at 6.8 ppm, again integrating to 2H. There is a singlet at 4.5 ppm, integrating to 1H. There is a quartet at 3.4 ppm integrating to 2H, and lastly there is triplet at 1.2 ppm integrating to 3H. i recofnize the ethyl group but don't understand the peak at 9.6 unless it is not an aldehyde.
- How could 1H NMR spectroscopy be used to distinguish betweencompounds X and Y?MS Spectrum (El) of the Unknown Organic Compound عل هلسهلهسيليسللنهدبلسلسسلبيلسهلهيد 80 60 140 160 180 200 220 20 40 100 120 m/z Provide mechanistic explanations for fragmentations in the following spectrum 147 145 175 173 177 188 061 216 218A compound has the molecular formula: C4H8O2 and gives the following C-13 NMR spectrum. Provide the most likely functional groups for each signal. nmrsim presentation 1 1 C:Bruken Topspin3.5pl7 examdata -170.7658 150 100 d 170.8 (O CH3) ; 60.4 (OCH2); 20.8, 14.1 (2 x C=0) 8170.8 (0 CH₂); 60.4 (OCH₂); 20.8, 14.1 (2 x CH3). 8 170.8 (CH3); 60.4 (C-0); 20.8, 14.1 (2 x OCH₂) 8170.8 (C=0); 60.4 (OCH₂); 20.8, 14.1 (2 x CH3). 8170.8 (C) ; 60.4 (O CH2); 20.8, 14.1 (2 x O CH3) -60.4293 50 -20.7902 -14.1385 [ppm] [+]
- draw the structure of the solid organic compound by the the help of c13 NMR spectra, label each equivalent set of Carbons as A, B,C etc and explain the whole process of determining the identity of the compound.How could 1H NMR spectroscopy be used to distinguish among isomers A, B, and C?Draw the structure of the compound identified by the simulated 'H NMR and 13C NMR spectra. The molecular formula of the compound is C1,H120. (Blue numbers next to the lines in the 'H NMR spectra indicate the integration values.) Η NMR 1H 2H 2H 2H 2H 3H| 10 8 4 2 8 (ppm) 13C NMR 220 200 180 160 140 120 100 80 60 40 20 d (ppm)