Figure 2G0.75 m2 m1.5 mFigure 2 shows a 2000 kg lorry with a center of mass at G. Starting from rest, the lorry achievesa speed of 15 m/s under a constant acceleration after it has traveled 100 m. The front wheels arefree to roll.Q8.What is the normal force of the wheels at A and B? (↑)(A) NA = 10.7 kN (B) NẠ=8.89 kN (C) NA= 8.89 kN (D) NA=10.7 kNNg = 8,89 kNNg = 10.7 kNNg = 8,89 kNNg = 10.7 kNQ11. Eccentric impact occurs when the line connecting the mass centers of the two bodieswith the line of impact.(A)coincide(В)does not coincide(С)is parallel(D) is perpendicularQ12. Which of the following is not a conservative force?(A) Gravitational force(B) Elastic force(C)Frictional force(D)None of the above

Answered: Image /qna-images/answer/7525d3d6-6fe8-472b-93dd-0f29718f15f6.jpg

Figure 2 shows a 2000 kg lorry with a center of mass at G. Starting from rest, the lorry achieves a speed of 15 m/s under a constant acceleration after it has traveled 100 m. The front wheels are free to roll. Q8. What is the normal force of the wheels at A and B? ( ↑ ) (A) NA = 10.7 kN (B) NẠ=8.89 kN (C) NẠ=8.89 kN (D) NA=10.7 kN Ng =8.89 kN Ng = 10.7 kN Ng = 8.89 kN Ng = 10.7 kN

Figure 2 shows a 2000 kg lorry with a center of mass at G. Starting from rest, the lorry achieves a speed of 15 m/s under a constant acceleration after it has traveled 100 m. The front wheels are free to roll. Q8. What is the normal force of the wheels at A and B? ( ↑ ) (A) NA = 10.7 kN (B) NẠ=8.89 kN (C) NẠ=8.89 kN (D) NA=10.7 kN Ng =8.89 kN Ng = 10.7 kN Ng = 8.89 kN Ng = 10.7 kN

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter7: Dry Friction

Section: Chapter Questions

Problem 7.81P: Calculate the horizontal force P required to push the 85-lb lawn mower at constant speed. The center...

See similar textbooks

Similar questions

A constant moment M in the clockwise direction is applied to a 20-lb thin disk in contact with an inclined surface. The kinetic friction coefficient is at the point of contact D. Determine the magnitude of the angular acceleration of the disk by neglecting the weight of the link AB, if M = 7.5 lb-ft and =0.4. Present your answer in rad/sec² using 3 significant figures. 1 in = 1/12 ft. 9 in. B M 30° D
A constant moment M in the clockwise direction is applied to a 20-lb thin disk in contact with an inclined surface. The kinetic friction coefficient is k at the point of contact D. Determine the magnitude of the angular acceleration of the disk by neglecting the weight of the link AB, if M = 7.5 lb-ft and = 0.4. Present your answer in rad/sec² using 3 significant figures. 1 in = 1/12 ft. 9 in. B M 30° D
Q5/ A car moving along a level road are having the following data: Wheel base of the car = 2.8 m; distance of C.G. from ground surface =600 mm; perpendicular distance of C.G. from rear axle = 1.2 m; speed on level road = 50 km/h; u minimum distance in which the car may be stopped when brakes are applied to the (i) rear wheels only, (ii) front wheels only and (iii) all the four wheels. = 0.6. Determine the
A cart (20 kg) is supported by 2 wheels (15 kg each) on a 30 degree incline. The wheels have a radius of 100mm and roll without slipping. WHAT IS THE ACCELERATION OF THE CART AFTER ITS RELEASED FROM REST?
consider the mass and pulley system in the attached file. mass m1 = 29 kg and mass m2 = 12kg. the angle of the inclined plane is given and the coefficient of kinetic friction between mass m2 and the inclined plane is uk = 0.12. assume the pulleys are massless and frictionless what is the acceleration of mass m2 on the inclined plane? take positive acceleration to be up the ramp a2 = ?
B r P F A UBC Engineering Your team is prototyping a simple braking system for your model car. The 3.4 kg wheel with a radius of r = rad 0.15 m is rotating at w = 18 - .A servo motor can apply a variable force F, which in its first two seconds of operation is equal to F = 10t N and afterwards is equivalent to a constant force of F = 20 N . If the coefficient of kinetic friction between the braking arm and the wheel is μ= 0.2, determine the time needed for the wheel to come to a full stop. The point of contact P between the wheel and the arm is a distance r = -0.2 + 0.26 ĵ m from point A. The force of the servo motor is applied at exactly half of the horizontal distance to A from the point of contact. Assume the wheel can be treated as a disk and that the braking arm is massless. t =
The below figure shows a cylinder of 13 kg mass, 0,3 m radius, undergoing unconstrained planar motion under the action of two forces F1=181 N and F2=76 N as shown. Calculate the angular acceleration of the cylinder in rad/s2. (Hint: I=½mr2) (If the direction of the angular acceleration is CCW, just enter the value of it without any sign. If it has CW direction, enter "-" sign "negative sign" before the value such as "- 12,12". Allowable tolerance for this question is relatively 2 percent.) F2 Fi
A vehicle weighs 1.6tons and for each wheel the diameter is 5.7m and the Mass moment of inertia is 4.7kg.m2. The coefficient of friction between the wheels and the road surface is 0.28. Calculate the deceleration of the vehicle if all of the wheels are locked after the brakes are suddenly applied. Given g=9.81m/s 2 (give answer as positive value)
weighs 60 N on Earth. (3). A system consists of a pulley (vertical wheel) that is only allowed to rotate (spin). A cord is passed over the pulley and at each end there is a mass attached to the end of the cord. The mass attached on the left is m, =0.6 kg and at the right the mass is m2 = 0.8 kg. a) Calculate both the Tension in the cord and the acceleration of the system. b) What are the accelerations of both masses, if you were to cut the cord? Neglect the friction between cord and wheel,
block C mass = 99 kg block D mass = 66kg horizontal force (H) = 555N and is applied at block D. Angle = 32.779 degrees note: Ignore friction. Computations must follow D'Alembert's Principle or else the solution is null and void. And answers should be in Newtons or KiloNewtons 1.) Calculate the Normal Force of Contact between blocks D and C. 2.) Determine the Block D Acceleration 3.) Determine the Block C Acceleration
Q Search 1. The ramp in Figure is frictionless. If the blocks are released from rest, which way does the 10 kg block slide, and what is the magnitude of its acceleration? 10 kg S0kg 40 2. In the diagram below, block A weighs 100N. The coefficient of static friction between the block and the surface on which it rests is 0.40. Find the maximum weight w for which the sVstem will remain in equilibrium.
Net torque, moment of inertia, and constant angular acceleration The radius of the roll of paper shown below is 7.6 cm and its moment of inertia is I= 3.3 x 10-3 kg-m². The roll is initially at rest, then a downward force F = 3.5 N is exerted on the end of the roll for 1.3 s, as shown. A constant frictional torque (Tf.) with magnitude 0.11 N-m that slows the clockwise rotation acts on the roll from the moment it starts rotating until the moment it stops rotating. After the force F is removed (at the end of 1.3 s), the roll slows and eventually comes to a stop due to tr. Assume that the paper is so thin that the radius of the roll remains constant while it is unrolling. (a) Calculate the total length of paper that unrolls from the moment the force F was applied until the moment that the roll stops moving. (answer: 7.3 m) (b) The thickness of the paper is about 0.01 cm. Is the assumption that the radius of the roll remained constant justified? That is, estimate the fractional decrease in…