Final design results are rounded to or fixed to three digits because the given data cannot justify a greater display. In addition, prefixes should be selected so as to limit number strings to no more than four digits to the left of the decimal point. Using these rules, as well as those for the choice of prefixes, solve the following relations: (a) o = M/Z, where M=1800 lbf-in and Z=0.931 in³ (b) a = F/A, where F=9440 lbf and A = 23.8 in² (c) y = FR³13EI, where F= 270 lbf, /= 31.5 in, E = 30 Mpsi, and /= 0.154 in 4 (d) 0 = TI/GJ, where T=9710 lbf - in, /= 9.82 in, G=11.6 Mpsi, and J= π 132 with d=1.03 in The corresponding values after solving the problem are (a) [ kpsi, (b)| psi, (c) in, and (d) x 10-2 rad.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Final design results are rounded to or fixed to three digits because the given data cannot justify a greater display. In addition, prefixes
should be selected so as to limit number strings to no more than four digits to the left of the decimal point. Using these rules, as
well as those for the choice of prefixes, solve the following relations:
(a) o = M/Z, where M= 1800 Ibf-in and Z= 0.931 in3
(b) o = FIA, where F= 9440 lbf and A = 23.8 in2
(c) y = FP13EI, where F= 270 Ibf, I = 31.5 in, E= 30 Mpsi, and /= 0.154 in4
(d) e = TII GJ, where T= 9710 Ibf - in, /= 9.82 in, G=11.6 Mpsi, and J= T d132 with d= 1.03 in
The corresponding values after solving the problem are (a)
|kpsi, (b)
|psi, (c)
in, and (d)
10-2 rad.
Transcribed Image Text:Final design results are rounded to or fixed to three digits because the given data cannot justify a greater display. In addition, prefixes should be selected so as to limit number strings to no more than four digits to the left of the decimal point. Using these rules, as well as those for the choice of prefixes, solve the following relations: (a) o = M/Z, where M= 1800 Ibf-in and Z= 0.931 in3 (b) o = FIA, where F= 9440 lbf and A = 23.8 in2 (c) y = FP13EI, where F= 270 Ibf, I = 31.5 in, E= 30 Mpsi, and /= 0.154 in4 (d) e = TII GJ, where T= 9710 Ibf - in, /= 9.82 in, G=11.6 Mpsi, and J= T d132 with d= 1.03 in The corresponding values after solving the problem are (a) |kpsi, (b) |psi, (c) in, and (d) 10-2 rad.
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