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- The rms value of v(t)=Vmaxcos(t+) is given by a. Vmax b. Vmax/2 c. 2Vmax d. 2VmaxReduce to its simplest form using msopErerrises: IA platinum oil has a resifance of 3-14k r at go°C and 3.747JV at 100°C.- Fin'd the resistance at o'C ond the kmp -creff. of resifonce af 40°C 2. A pofential difference of r5oV is apphed to a field wnding at 15°C and the currend is SA. What will be the mean fempouafure of the winiding when currend has falen to 3.91A, apphedvrltage being constant Aasume s =p7.5. 3. A cril has a resi fance of 182 when its mean femperature is 20°C and 20v when ik mean femperature s 50°C. Frid is mean femperature rise when ik resotonce is 21JL and the sorrandinig femperature is i5°C. A cril of a relay takes a curre of 0.12 A when it is at the vem insbi o al 4. A jemperature of is'C ond canneckerdacms a oV supply If the minimum operating current of the relay is 0.1 A, colculate the femperature above ohich the relay will fail to operate when connected ti the same supply. Resi tncenfemp.coefficrenf of the cril makria] is o.0043 per °C at 0°C.
- A certain impedance is given by 1012° N. Does the current lead or lag the voltage, and by how many degrees? Fill in the blanks. The current the voltage byRo. 8. For unit- slep responses A,4 find the homafor the system. chowa ahe figure , 20 see tlJae) fimetion ofgoogle.com/forms/d/e/1FAlpQLScF2Wzu92iVI-tEM2nxdhqXrGdR460G4QCTxaUZZeC678PqTg/formResponse مطلوب /06 *:The potential at point P due to Q1 and Q2 is Q, = 1x10-12C 0.5 m 0.5 m Qz = 1x10-12C %3D 50 cm 0.01797 V Ov O -0.01271 V O 0.01271 V O Insert PIC F10 F11 F12 F6 F7 FB Backspace 9 € P Enter H
- If A = 20260° and B= 5230°, find the products AB and BB".Ac - 100 VrmsR1 - 1kR2 - 500Rload - 1kCapacitor - 2uF Q1. How much is the capacitor voltage lagging from the AC source2, Zs Z7 Solve for: Solve for: h.) S5 i.) P6 j.) Q7 Given: E = 1002 – 90 volts Z4 = 42450 Z1 = 1200 Z5 = 5453.13N Z2 = 2436.87N Z6 = 62 – 90N Z3 = 32 - 30N Z, = 72750
- Exercise-1 Vs = 240V 60Hz Is=10A/....... Power system Is ww R 1k0 Xc=-j/(2pi60x0.00016)=-1994 XL=ZL=j2pifl=j2pi60x0.142=j53.54 142mH Is=Ir+IL+Ic=.........=Vs/Ztotal=....... 160μFShow that the following property of the twiddle factor is valid: WNk+N=WNkA) find Ztot in rectangular form B) find Ztot in polar form C) find V1 or VL in polar for. ( use voltage divider rule or ohm law).