Find the absolute extrema of the function on the closed interval. y = = 3x2/3 - 2x, [-1, 1] (x, y) = minimum maximum (x, y) =

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 41E
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Find the absolute extrema of the function on the closed interval.
у - 3x2/3 - 2х, [-1, 1]
(х, у) 3D (
minimum
maximum
(х, у) %3D
Transcribed Image Text:Find the absolute extrema of the function on the closed interval. у - 3x2/3 - 2х, [-1, 1] (х, у) 3D ( minimum maximum (х, у) %3D
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