Find the value of P(X>9)
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Find the value of P(X>9)
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- Please give the first Q1 for this dataPlease give Q2 for this dataThe following equations were estimated using the data in BWGHT: log(bwght) = 4.66 - 0044 cigs + .0093 log(faminc) + .016 parity (.0059) (.22) (.0009) (.006) + .027 male + .055 white (.010) (.013) 1,388, R = .0472 and log(bwght) 4.65 – .0052 cigs + .0110 log(faminc) + .017 parity (.006) (.38) (.0010) (.0085) + .034 male + .045 white – .0030 motheduc + .0032 fatheduc (.011) (.015) (.0030) (.0026) n = 1,191, R2 = .0493. %3D
- %5D%2C"action"%3A"open"%2C"userld*%3A 1058667002127212725. O 175% Turn In 32. 10 13Given the data points (2, 29.5), (5, 523), (7, 1807), and (11, 9853), find the value of f(x) if x = 3.79 using linear interpolation. Round off your final answer to five decimal places but do not round off in preliminary calculations. Round your answer to 5 decimal places. Correct answer: 323.95500Calculate x by reverse interpolation, which gives the value of f(x)=2 in the dataset
- Use the following equation to prove that : If we multiply the data values by a constant (say, c), this will not affect the geometric mean. And give an example.The Transylvania hypothesis claims that the full moon has an effect on health-related behavior. A study investigating this effect found a significant relationship between the phase of the moon and the (x-4) + 100 where y is the number of consultations as a percentage of the daily mean and x is the days since the last full 15.12 number of general practice consultations nationwide, given by y = 1.9 cos moon. a. What is the period of this function? What is the significance of this period? The period is days. (Round to two decimal places as needed.) Choose the correct meaning of the period p in the context of the problem. The x-distance between the maximum and the minimum of the graph is p. Every p days there is a full moon. There were p% more consultations when there was a full moon. The average number of daily consultations is p. b. If there was a full moon on April 7, on what day in April does this formula predict the maximum number of consultations? What percent increase would be…Extensive scientific research on nerve conduction has led to the conclusion that the mean refractory period in a healthy rat is 1.3 millisecond (ms). An experiment designed to study the effect of the pesticide DDT on nerve conduction finds that the mean refractory period of 4 rats poisoned with DDT is 1.75 ms. The number 1.3 is a ________ and then number 1.75 is a ____________. A. statistic, statistic B. statistic, parameter C. parameter, statistic D. parameter, parameter
- High levels of cockpit noise in an aircraft can damage the hearing of pilots who are exposed to this hazard for many hours. Cockpít noise in a jet aircraft is mostly due to airflow at hundreds of miles per hour. This 3 x 3 contingency table shows 61 observations of dat collected by an airline pilot using a handheld sound meter in a certain aircraft cockpit. Noise level is defined as "low" (under 88 decibels). "medium" (88 to 91 decibels), or "high" (92 decibels or more). There are three flight phases (climb, cruise, descent). Cockpit Noise Flight Phase Cruise (C) Noise Level CLimb (B) Descent (D) Row Total 14 Low (L) Medium (M) High (H) 8. 4. 17 8. 6 31 2. 11 16 Column Total 27 13 21 61 Click here for the Excel Data File (a) Calculate the following probabilities: (Round your answers to 4 declmal places.) P(B) ii. PL) i. P(H|C) iv. P(H|D) i. v. P(L and B) vi. P(L and C) (b) Do you see evidence that noise level depends on flight phase? O Yes O No raw ill arcos! < Prev 61Given the data points (1, 13), (4, 235), (8, 2974), and (10, 6875.5), find the value of f(x) if x = 3.21 using quadratic interpolation. Round off your final answer to five decimal places but do not round off in preliminary calculations. Answer: 24.21023The authors of an article found that the speed of a prey (twips/s) and the length of a prey (twips ✕ 100) are good predictors of the time (seconds) required to catch the prey. (A twip is a measure of distance used by programmers.) Data were collected in an experiment in which subjects were asked to "catch" an animal of prey moving across his or her computer screen by clicking on it with the mouse. The investigators varied the length of the prey and the speed with which the prey moved across the screen. The following data are consistent with summary values and a graph given in the article. Each value represents the average catch time over all subjects. The order of the various speed-length combinations was randomized for each subject. Prey Length Prey Speed Catch Time 7 20 1.11 6 20 1.20 5 20 1.24 4 20 1.40 3 20 1.50 3 40 1.41 4 40 1.35 6 40 1.31 7 40 1.28 7 80 1.40 6 60 1.39 5 80 1.40 7 100 1.42 6 100 1.42 7 120 1.69 5 80 1.49 3 80 1.41 6 100 1.49…
