For a system consist from 3 buses and bus 1 is the slack bus. The data of thesystem are:-0.25Ybusj -0.2-0.20.225-0.05 -0.025-0.05-0.025 p.u.0.075V₁=1+j0 p.u., P₂+jQ=0.6+j0.25 p.u., P3+jQ3-0.8+j0.5 p.u.-0.762-j0.826-0.762+10.826O 0.762+j0.8260.762-j0.826By using Gauss-Siedal method, the voltage of the bus 2 after two iterationis

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For a system consist from 3 buses and bus 1 is the slack bus. The data of the system are:- 0.25 -0.2 -0.05 Ybus-j-0.2 0.225 -0.025 p.u. -0.05 -0.025 0.075 V₁=1+j0 p.u., P₂+jQ2-0.6+j0.25 p.u., P3+jQ3-0.8+j0.5 p.u. By using Gauss-Siedal method, the voltage of the bus 2 after two iteration is Pa

For a system consist from 3 buses and bus 1 is the slack bus. The data of the system are:- 0.25 -0.2 -0.05 Ybus-j-0.2 0.225 -0.025 p.u. -0.05 -0.025 0.075 V₁=1+j0 p.u., P₂+jQ2-0.6+j0.25 p.u., P3+jQ3-0.8+j0.5 p.u. By using Gauss-Siedal method, the voltage of the bus 2 after two iteration is Pa

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.12MCQ

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Question

For a system consist from 3 buses and bus 1 is the slack bus. The data of the
system are:-
0.25
Ybusj -0.2
-0.2
0.225
-0.05 -0.025
-0.05
-0.025 p.u.
0.075
V₁=1+j0 p.u., P₂+jQ=0.6+j0.25 p.u., P3+jQ3-0.8+j0.5 p.u.
-0.762-j0.826
-0.762+10.826
O 0.762+j0.826
0.762-j0.826
By using Gauss-Siedal method, the voltage of the bus 2 after two iteration
is

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For a system consist from 3 buses and bus 1 is the slack bus. The data of the system are:- 0.25 Ybus j -0.2 -0.2 -0.05 0.225 -0.025 p.u. -0.05 -0.025 0.075 V₁=1+j0 p.u., P₂+jQ₂=0.6+j0.25 p.u., P3+jQ3=0.8+j0.5 p.u. By using Gauss-Siedal method, the voltage of the bus 3 after two iteration is -0.076+j0.5566 O -0.076-j0.5566 O 0.076+j0.5566 0.076-j0.5566
For a system consist from 3 buses and bus 1 is the slack bus. The data of the system are:- -0.2 -0.05 Ybus-j-0.2 0.225 -0.025 p.u. -0.05 -0.025 0.075 V₁=1+j0 p.u., P₂+jQ=0.6+j0.25 p.u., P3+jQ3-0.8+j0.5 p.u. 0.25 By using Gauss-Siedal method, the voltage of the bus 2 after two iteration is -0.762-j0.826 -0.762+j0.826 0.762+j0.826 0.762-j0.826 By using Gauss-Siedal method, the voltage of the bus 1 after two iteration is 1+j0 0+j1 -0.3-j0.6 0.3-j0.6
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