For the Ricker model given by P = Pn_1e 1.76(1-1) a) Which of the following is correct strategy for finding the equilibrium values algebraically? Solve the equation Pee¹-76(1-#) - 0 for Pe ○ Solve the equation Pe = Pe Plug O into the DDS = 1.76(1) for Pe b) The equilibrium values are 0 and c) Iterations of the model starting from the single initial value = 85 are graphed below. 90 08 . . . • . 3 4 5 6 9 8 70- Which of the following description of the non-zero equilibrium value is correct? O The equilibrium is unstable because the values are moving (zig-zagging) away from the equilibrium value. The equilibrium is unstable because the values are not always increasing. The equilibrium is stable because the values are moving (zig-zagging) toward the equilibrium value. The equilibrium is stable because the values are not negative. For the Beverton-Holt model given by the DDS Pr 2.94Pm-1 1+0.002P 1 a) Choose the correct method for finding the equilibrium values. O Solve the equation 2.94P 1+0.002P = 0 for Pe Plug O into the DDS Solve the equation Pe 2.94Pc 1+0.002Pe for Pe b) The equilibrium values are 0 and c) Iterations of the model starting from ze=980 and zo=920 are graphed below. 1080+ 1060- 1040- 1020- 1000 980 960 940- 920 900- -1880 1 2 3 4 5 6 7 8 9 1 Use the graph of the population sequences to determine the stability of the non-zero equilibrium value. Which of the following is the correct statement? The equilibrium is stable because the values are moving toward the equilibrium value on both sides. The equilibrium is unstable because the values are moving away from the equilibrium value on both sides. The equilibrium is unstable because the values are not always increasing. ○ The equilibrium is stable because the values are not negative.