For the common allotropes of carbon (graphite and diamond), C(gr) ⟷⟷ C(dia) with equilibrium constant K = 0.32. The molar volumes of graphite and diamond are, respectively, 5.30 cm3/mol and 3.42 cm3/mol; ΔHf of diamond is 1.90 kJ/mol. These data suggest that the formation of diamond is favored at Group of answer choices None of the answers is correct. low temperatures and high pressures. high temperatures and high pressures. low temperatures and low pressures. high temperatures and low pressures
For the common allotropes of carbon (graphite and diamond), C(gr) ⟷⟷ C(dia) with equilibrium constant K = 0.32. The molar volumes of graphite and diamond are, respectively, 5.30 cm3/mol and 3.42 cm3/mol; ΔHf of diamond is 1.90 kJ/mol. These data suggest that the formation of diamond is favored at Group of answer choices None of the answers is correct. low temperatures and high pressures. high temperatures and high pressures. low temperatures and low pressures. high temperatures and low pressures
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
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Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.157QP: Consider the Haber process: N2(g)+3H2(g)2NH3(g);H=91.8kJ The density of ammonia at 25C and 1.00 atm...
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For the common allotropes of carbon (graphite and diamond), C(gr) ⟷⟷ C(dia) with equilibrium constant K = 0.32. The molar volumes of graphite and diamond are, respectively, 5.30 cm3/mol and 3.42 cm3/mol; ΔHf of diamond is 1.90 kJ/mol. These data suggest that the formation of diamond is favored at
Group of answer choices
None of the answers is correct.
low temperatures and high pressures.
high temperatures and high pressures.
low temperatures and low pressures.
high temperatures and low pressures.
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