For the reaction HNC(g) → HCN (g) K = 8.0 If the initial concentration of HNC is 0.80 M, what is the equilibrium concentration of HCN? Express your answer to two significant figures.

Introductory Chemistry: A Foundation
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Chapter17: Equilibrium
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Problem 7ALQ: The value of the equilibrium constant, K, is dependent on which of the following? (There may be more...
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Question 8
For the reaction
HNC(g) → HCN(g)
If the initial concentration of HNC is 0.80 M, what is the equilibrium
concentration of HCN? Express your answer to two significant figures.
[HNC] = 0.71 X M
K = 8.0
Transcribed Image Text:Question 8 For the reaction HNC(g) → HCN(g) If the initial concentration of HNC is 0.80 M, what is the equilibrium concentration of HCN? Express your answer to two significant figures. [HNC] = 0.71 X M K = 8.0
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