Four-legged animals run with two different types of motion: trotting and galloping. An animal that is trotting has at least one foot on the ground at all times, whereas an animal that is galloping has all four feet off the ground at some point in its stride. The number of strides per minute at which an animal breaks from a trot to a gallop depends on the weight of the animal. Use the table and the method of this example to find an equation that relates an animal's weight x (in pounds) and its lowest galloping speed y (in strides pert minute). Weight, x 25 Galloping Speed, y 194.5 35 50 75 500 183.7 175.8 162.2 124.9 Take the natural logarithm of each coordinate to obtain points of the form (In x, In y). (Round your answers to three decimal places.) Weight, x Galloping Speed, y In x In y 25 194.5 Read It 35 183.7 1000 111.2 50 175.8 75 162.2 Find the least squares regression line for the transformed points. (Round your answers to three decimal places.) In y [ + In x 500 124.9 1000 111.2 Find an equation of the form y= ax that relates an animal's weight x (in pounds) and its lowest galloping speed y (in strides per minute). (Round your value for a to one decimal place and your value for b to three decimal places.) y= Need Help?
Four-legged animals run with two different types of motion: trotting and galloping. An animal that is trotting has at least one foot on the ground at all times, whereas an animal that is galloping has all four feet off the ground at some point in its stride. The number of strides per minute at which an animal breaks from a trot to a gallop depends on the weight of the animal. Use the table and the method of this example to find an equation that relates an animal's weight x (in pounds) and its lowest galloping speed y (in strides pert minute). Weight, x 25 Galloping Speed, y 194.5 35 50 75 500 183.7 175.8 162.2 124.9 Take the natural logarithm of each coordinate to obtain points of the form (In x, In y). (Round your answers to three decimal places.) Weight, x Galloping Speed, y In x In y 25 194.5 Read It 35 183.7 1000 111.2 50 175.8 75 162.2 Find the least squares regression line for the transformed points. (Round your answers to three decimal places.) In y [ + In x 500 124.9 1000 111.2 Find an equation of the form y= ax that relates an animal's weight x (in pounds) and its lowest galloping speed y (in strides per minute). (Round your value for a to one decimal place and your value for b to three decimal places.) y= Need Help?
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter5: Systems Of Equations And Inequalities
Section5.1: Systems Of Linear Equations In Two Variables
Problem 74E: Aerobic exercise a woman is spitfire by cycling and running every day. on Monday she spend half hour...
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Transcribed Image Text:Four-legged animals run with two different types of motion: trotting and galloping. An animal that is trotting has at least one foot on the ground at all times, whereas an animal that is galloping has all four feet off the ground at some point in its stride. The number of
strides per minute at which an animal breaks from a trot to a gallop depends on the weight of the animal. Use the table and the method of this example to find an equation that relates an animal's weight x (in pounds) and its lowest galloping speed y (in strides per
minute).
In y
Weight, x
Galloping Speed, y
25
194.5
Take the natural logarithm of each coordinate to obtain points of the form (In x, In y). (Round your answers to three decimal places.)
Weight, x
Galloping Speed, y
In x
Need Help?
35
50
183.7 175.8
25
194.5
Read It
75
500
1000
162.2 124.9 111.2
35
183.7
50
175.8
Find the least squares regression line for the transformed points. (Round your answers to three decimal places.)
In y =
In x
75
162.2
500
124.9
Find an equation of the form y = axb that relates an animal's weight x (in pounds) and its lowest galloping speed y (in strides per minute). (Round your value for a to one decimal place and your value for b to three decimal places.)
y =
1000
111.2
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