Gaseous NOBr is placed in a closed container at -169 oC, where it partially decomposes to NO and Br2: 2 NOBr(g) 2 NO(g) + 1 Br2(g) At equilibrium it is found that p(NOBr) = 0.006710 atm, p(NO) = 0.008220 atm, and p(Br2) = 0.006020 atm. What is the value of KP at this temperature? KP =_______ .
Gaseous NOBr is placed in a closed container at -169 oC, where it partially decomposes to NO and Br2: 2 NOBr(g) 2 NO(g) + 1 Br2(g) At equilibrium it is found that p(NOBr) = 0.006710 atm, p(NO) = 0.008220 atm, and p(Br2) = 0.006020 atm. What is the value of KP at this temperature? KP =_______ .
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter12: Gaseous Chemical Equilibrium
Section: Chapter Questions
Problem 85QAP
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Gaseous NOBr is placed in a closed container at -169 oC, where it partially decomposes to NO and Br2:
2 NOBr(g) 2 NO(g) + 1 Br2(g)
At equilibrium it is found that p(NOBr) = 0.006710 atm, p(NO) = 0.008220 atm, and p(Br2) = 0.006020 atm. What is the value of KP at this temperature?
KP =_______ .
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