Give a possible formula for the function below. Let A y(x) = Y k B x 5). Use the general exponential tion.

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A: We have to find the area of the sector of a circle of radius 5 meters formed by an angle of 150°.

Q: 8.) 2x² - 19x + 35= 0 ( )( GCF: )=0

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Q: Solve cos(x)=−0.79 on 0≤x<2π There are two solutions, A and B, with A < B A= B=

A: Given:       cosx=-0.79 on 0≤x&lt;2π Solving for x using inverse cosine function.     cosx=-0.79…

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Q: (c) Prove that cos 35°+cos 45°+cos 75°+cos 85° = 2 cos 5° cos 20°.

A: Formula used: cosx+cosy=2cosx+y2cosx-y2cos(-x)=cosx

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A: Topic - implicit differentiation We are given7x2-y3=5we know thatddxxn=nxn-1

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A: I am attaching image so that you understand each and every step.

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A: Topic- inverse trigonometric values We are given, sin-1(2.12) We know that domain of sin-1(x) is…

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A: Given data:- The basic equations, sin(x) = 3sin(x) = 0.9

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A: Given query is to simplify the expression.

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Q: Use an appropriate half-angle formula to find the exact value of: sin 11pie/12

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Q: a 12m 3 4 16m Find the length of sides ad, dc b - 5 2 10 side be = 22m where bd = 10m and de = 12m…

A: To find the length of sides ad, and dc.To find ∠11.

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A: Here is the solution:

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A: Pythagorus theorem states that (Base)2+(Height)2=(Hypotenus)2  for a right angle triangle.

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A: We have to determine the three positive solution

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Q: Find the values of the trigonometric functions of from the information given. sec = 10, sin 0 < 0…

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Q: Using Properties of Dot Products In Exercises 11-16, use the vectors u = (2, 2), v = (-5, 3), and w…

A: Here we have to find the dot product.

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Q: Answer the following as required. 1) Determine the amplitude and period of y = -7 sin Amplitude: 2)…

A: If a function look like y=Asin(B(x+C))+D where A is amplitude, period is 2πBSame for cosine function

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A: We have to find the three positive solution

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Q: Convert the polar equation to rectangular coordinates. (Use variables x and y as needed.) r cos(0) =…

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Q: Consult the figure. To find the length of the span of a proposed ski lift from A to B, a surveyor…

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