Give your answer in SI units and to three significant figures. D Question 1 111 0 112 020 60° 104 112 111 Light is incident on the right side of a triangular prism, as shown. If 1 = 35.859, determine the angle with which the light emerges from the glass. Assume that the glass had an index of refraction of 1.448
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- A 45°-90°-45° prism is constructed from a synthetic resin. As shown in the figure, a light beam that enters the prism at the midpoint of the long side and parallel to the base exits the prism at an angle of 28° below the horizontal. What is the index of refraction of this prism? 1.39 Have you drawn a figure showing all angles and established any relationships between the angles? Have you written a Snell's law statement for the light as it enters and exits the prism? Depending on how you solve the problem, you may need the identities tan a = sin a / cos a and sin(a + 6) = sin a cos pi cos a sin ß. Additional Materials ReadingProblem 2: What is the smallest angle 1 for which a laser beam will undergo total internal reflection on the hypotenuse of the glass prism in figure? a. Draw the refracted and reflected rays inside the glass prism, and the refracted ray as it exits the prism. b. Clearly mark all angles. Show all your calculations here. Ꮎ 30° 60%Assignment: Ma M1 1. Two mirrors make an angle of 90 degrees with each other, as in the figure above. A ray is incident on the mirror M1 at an angle of 65 degrees to the normal. Find the angle the ray makes with the normal to M2 after it is reflected from both mirrors. 2. A ray strikes a water surface at an angle. The angle of refraction in water is found to be 20 degrees. What must be the angle of incidence of the light ray have been? N glass= 1.5525 : N air=1.00029. Use Snell's Law.
- M12A case sample is attached.Please solve the question number 1 and kindly use the formula in the photo attached. The answer is already given. Can you please show the solution how the answer is solved.1. A ray of light from within the diamond towards air, what is the angle of refraction if:a. the angle of incidence is 5 degrees? Answer: 12.18 degrees (please show the solution)b. the angle of incidence is 24.41 degrees? Answer: 90 degrees (please show the solution)2. What is the angle of deviation if a ray og light in diamond is incident at an angle of 32 degrees? ( this is an example of TIR)The diagram at the right shows a ray of light traveling through air towards a thin layer of linseed oil (n = 1.50) resting on top of water (n=1.33). The light ray approaches the linseed oil at an angle of incidence of 48.2°.a. Determine the angle of refraction at the air-linseed oil boundary.b. Determine the angle of refraction at the linseed oil-water boundary.Use the image to solve the problem. For n1 use the index of refraction of air, 1.000293. For n2 use the index of refraction of glass, 1.52. a) Determine the angle of refraction of light after it has entered the prism. b) Using geometry, determine the incident angle of the light on the side of the prism it is exiting. c)Determine the angle of refraction of light after it leaves the
- A ray of light travels through air until it strikes the interface between the air and another medium. The incident ray makes an angle of 0₁ into the second medium, the ray is refracted, emerging from the interface at an angle 02 with respect to the normal. O Air (a) Suppose that the second medium is fused quartz. What is the angle of refraction, 02 (in degrees)? (Enter your answer to at least one decimal place.) O Second medium = 56.0° with the normal, as shown in the figure below. Upon passage (b) Suppose that the second medium is sodium chloride. What is the angle of refraction, 02, in this case (in degrees)? (Enter your answer to at least one decimal place.) O (c) Finally, suppose that the second medium is glycerine. What is the angle of refraction, 02, in this case (in degrees)? (Enter your answer to at least one decimal place.)6. A sheet of glass has an index of refraction nalass = 1.45. Assume that the index of refraction for air is na= 1.00, Light is incident on the sheet of glass at an angle of incidence of 60°, as shown in the figure below. a. Calculate and label the size of each angle (in degrees) on the figure, including angles of incidence and refraction at each of the two parallel surfaces shown. 60 degrees Air na = 1.00 Glass " = 1.45 Air ng = 1.00 b. Calculate the velocity of the light as it travels in the glass.A ray of light strikes a flat, 2.00-cm-thick block of glass (n = 1.52) at an angle of ? = 37.4° with respect to the normal (see figure below). a.) Find the lateral distance d by which the light beam is shifted. b.) Calculate the time required for the light to pass through the glass block.
- M11A case problem is attached.1. A microscope is sharply focused on a mark at 5.7 cm. If a parallel plate of glass is placed over the mark, Where will the focus be if the index of refraction of the glass is 1.52?How Deep Is the Goldfish? A tank whose bottom is a mirror is filled with water to a depth of 20.4 cm. A small fish floats motionless 6.00 cm under the surface of the water. Part A What is the apparent depth of the fish when viewed at normal incidence to the water? Express your answer in centimeters. Use 1.33 for the index of refraction of water. ▸ View Available Hint(s) ΜΕ ΑΣΦ ? esc FI 1 2 0 A N W ह S X r" command # 3 20 F3 Submit Part B cm What is the apparent depth of the reflection of the fish in the bottom of the tank when viewed at normal incidence? Express your answer in centimeters. Use 1.33 for the index of refraction of water. ▸ View Available Hint(s) ΜΕ ΑΣΦ Submit Provide Feedback F5 ? cm বর Dll 18 F9 $ % ^ & 4 5 6 7 8 9 E R T Y U D FL G H J K C V B N M 06. A sheet of glass has an index of refraction nglass = 1.36. Assume that the index of refraction for air is nair = 1.00. Light is incident on the sheet of glass at an angle of incidence of 60°, as shown in the figure below. a. Calculate and label the size of each angle (in degrees) on the figure, including angles of incidence and refraction at each of the two parallel surfaces shown. 60 degrees Air na = 1.00 Glass ng = 1.36 Air na = 1.00 %3D b. Calculate the velocity of the light as it travels in the glass.