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Given the following polynomial, p(x)=3x³-6x² +11x-8 ± ( According to the rational zero theorem, the possible zeros for p(x) are 1,2,4,8 1,3 It turns out x= 1 is a true zero of p(x). You can perform synthetic division to rewrite p(x) in the factored form given below. Find the values for a,b,c. p(x) = (x - 1)(ax²+bx+c)

Given the following polynomial, p(x)=3x³-6x² +11x-8 ± ( According to the rational zero theorem, the possible zeros for p(x) are 1,2,4,8 1,3 It turns out x= 1 is a true zero of p(x). You can perform synthetic division to rewrite p(x) in the factored form given below. Find the values for a,b,c. p(x) = (x - 1)(ax²+bx+c)

College Algebra
College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter5: Polynomial And Rational Functions
Section: Chapter Questions
Problem 13PT: Use the Rational Zero Theorem to help you find the zeros of the polynomial functions....
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Given the following polynomial, p(x)=3x³-6x² +11x-8 According to the rational zero theorem, the possible zeros for p(x) are + It turns out x= 1 is a true zero of p(x). You can perform synthetic division to rewrite p(x) in the factored form given below. Find the values for a,b,c. p(x) = (x - 1)(ax²+bx+c) a = b = C = A 1,2,4,8 1,3 A/
Transcribed Image Text:Given the following polynomial, p(x)=3x³-6x² +11x-8 According to the rational zero theorem, the possible zeros for p(x) are + It turns out x= 1 is a true zero of p(x). You can perform synthetic division to rewrite p(x) in the factored form given below. Find the values for a,b,c. p(x) = (x - 1)(ax²+bx+c) a = b = C = A 1,2,4,8 1,3 A/
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