Given the thermochemical equations X₂ + 3Y₂ → ->> 2XY, X₂ +2Z₂ → 2XZ₂ ΔΗ, = -160 kJ 2Y₂+Z₂2Y₂Z AH3 = -240 kJ Calculate the change in enthalpy for the reaction. 4XY3 +7Z₂ → 6Y₂Z+4XZ₂ AH = AH = -320 kJ kJ

Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter15: Energy And Chemical Change
Section: Chapter Questions
Problem 71A
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Given the thermochemical equations
X₂ + 3Y₂ → 2XY3
->>
X₂ +2Z₂ → 2XZ₂
AH₂ = -160 kJ
2Y₂+Z₂2Y₂Z
AH3 = -240 kJ
Calculate the change in enthalpy for the reaction.
4XY3 +7Z₂6Y₂Z +4XZ₂
AH =
AH = -320 kJ
kJ
Transcribed Image Text:Given the thermochemical equations X₂ + 3Y₂ → 2XY3 ->> X₂ +2Z₂ → 2XZ₂ AH₂ = -160 kJ 2Y₂+Z₂2Y₂Z AH3 = -240 kJ Calculate the change in enthalpy for the reaction. 4XY3 +7Z₂6Y₂Z +4XZ₂ AH = AH = -320 kJ kJ
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