H3PO4 + 3 Mg(OH)2 → Mg3(PO4)2 + 6 H2O (MM = 97.97) (MM = 58.32) (MM = 262.86) (MM = 18.02) How many grams of H3PO4 must react to produce 0.547 moles of H2O?
H3PO4 + 3 Mg(OH)2 → Mg3(PO4)2 + 6 H2O (MM = 97.97) (MM = 58.32) (MM = 262.86) (MM = 18.02) How many grams of H3PO4 must react to produce 0.547 moles of H2O?
General, Organic, and Biological Chemistry
7th Edition
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:H. Stephen Stoker
Chapter6: Chemical Calculations: Formula Masses, Moles, And Chemical Equations
Section: Chapter Questions
Problem 6.71EP: How many moles of beryllium (Be) are needed to completely react with 10.0 moles of N2 in the...
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2 H3PO4 + 3 Mg(OH)2 → Mg3(PO4)2 + 6 H2O
(MM = 97.97) (MM = 58.32) (MM = 262.86) (MM = 18.02)
How many grams of H3PO4 must react to produce 0.547 moles of H2O?
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