AHBr (1 equiv)H₂O₂escSelect to Draw!1OF1143,177@2F2#3DEC31 680F3$4QF4CIO%5stv0F54JONA6GF6A&7KBDF78DIIF8HCI (1 equiv)NaCl (2 equiv)4waterCla (1 equiv)HCI (excess)(0DoneDD9F9)0F10F11F12 A common alkyne starting material is shown below. Predict the major product or missingreagent to complete each reaction. Ignore inorganic byproducts.thescB!1UF1143,177@2F2#3BASelect to Draw1. NaNha2. CH₂CH₂CH₂ClDEC31 680F3$4QF4%5tv ONA0F5A6CF6&7AF7BCD*8F84HI(1 equiv)HI (excess)Nalwaterlz (1 equiv)(DD90DoneF9F100dF11+F12

Markovnikov rule, the hydrogen atom is attached to the carbon atom with the highest number of…

HBr (1 equiv) H₂O₂ esc Select to Draw ! 1 O F1 143.177 XX @ 2 F2 # 3 DEC 31 6 80 F3 $ 4 Q F4 CI % 5 tv 0 F5 JON A 6 G F6 A & 7 K B D F7 * 8 DII F8 HCI (1 equiv) NaCl (2 equiv) 1 water Cla (1 equiv) HCI (excess) ( O Done DD 9 F9 A ) 0 F10 F11 Jol) + F12

HBr (1 equiv) H₂O₂ esc Select to Draw ! 1 O F1 143.177 XX @ 2 F2 # 3 DEC 31 6 80 F3 $ 4 Q F4 CI % 5 tv 0 F5 JON A 6 G F6 A & 7 K B D F7 * 8 DII F8 HCI (1 equiv) NaCl (2 equiv) 1 water Cla (1 equiv) HCI (excess) ( O Done DD 9 F9 A ) 0 F10 F11 Jol) + F12

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

A
HBr (1 equiv)
H₂O₂
esc
Select to Draw
!
1
O
F1
143,177
@
2
F2
#
3
DEC
31 6
80
F3
$
4
Q
F4
CI
O
%
5
stv
0
F5
4
JON
A
6
G
F6
A
&
7
K
B
D
F7
8
DII
F8
HCI (1 equiv)
NaCl (2 equiv)
4
water
Cla (1 equiv)
HCI (excess)
(
0
Done
DD
9
F9
)
0
F10
F11
F12

A common alkyne starting material is shown below. Predict the major product or missing
reagent to complete each reaction. Ignore inorganic byproducts.
th
esc
B
!
1
U
F1
143,177
@2
F2
#
3
BA
Select to Draw
1. NaNha
2. CH₂CH₂CH₂Cl
DEC
31 6
80
F3
$
4
Q
F4
%
5
tv ONA
0
F5
A
6
C
F6
&
7
A
F7
B
C
D
*
8
F8
4
HI(1 equiv)
HI (excess)
Nal
water
lz (1 equiv)
(
DD
9
0
Done
F9
F10
0
d
F11
+
F12

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