he Turing machine that computes the function f(x,y) =x+2y, with both x and y positive integers.
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- Show that the following function is Turing-computable. f(x)=x+1 . I want the drawing4. LetΣ ={a, b}. LetL={aibai|i≥0}.Give a Turing machine (TM) that accepts the languageL.Assume (as in the examples done in our course videos) that, when theTM starts, the head is on a blank symbol,∆, and the input string isimmediately after that blank symbol on the tape. For example, if theinput string wereaaabaaa, then the inital tape configuration would be∆aaabaaaYou will disappoint me if you solve it without drawing I just want you to draw me the following question please: Turing machine that computes the function f(x,y) = x+2y, with both x and y strictly positive integers.
- Let L be a line in the xy plane. If L is a vertical line, its equation is x=afor some real number a. Suppose L is not a vertical line and its slope is m. Then the equation of L is y=mx + b, where b is the y-intercept. If L passes through the point (x0,y0), the equation of L can be written as y –y0=m(x –x0). If (x1,y1)and (x2,y2)are two points in the xy plane and x1≠x2, the slope of the line passing through these points is m = (y2-y1)/ (x2-x1). Write a program that prompts the user to enter two points in the xy plane. The program outputs the equation of theline and uses ifstatements to determine and output whether the line is vertical, horizontal, increasing, or decreasing. If L is a nonvertical line, output its equation in the form y=mx + b.8. Give a Turing machine that computes the function f(w)= ww", where we {a,b}* and w is the reverse of w.The reverse function maps a string w to wR. Draw a multi-tape Turing machine that computes the reverse of a binary string. That is, given a binary string w as input, your Turing machine should compute wR, write the result to tape 1, and halt.
- Example 9.7 For E = {a,b}, design a Turing machine that accepts L= {a,b„:n21}. Intuitively, we solve the problem in the following fashion. Starting at the leftmost a, we check it off by replacing it with some symbol, say x. We then let the read-write head travel right to find the leftmost b, which in turn is checked off by replacing it with another symbol, say y. After that, we go left again to the leftmost a, replace it with an x, then move to the leftmost band replace it with y, and so on. Traveling back and forth this way, we match each a with a corresponding b. If after some time no a's or b's remain, then the string must be in L. Working out the details, we arrive at a complete solution for which Q= {qo91;9293,94},F= {q4}, E= {a,b},T={a,b, x, y,¤}. The transitions can be broken into several parts. The setCorrect answer will be upvoted else downvoted. Computer science. You are given a grid a comprising of positive integers. It has n lines and m segments. Develop a framework b comprising of positive integers. It ought to have a similar size as a, and the accompanying conditions ought to be met: 1≤bi,j≤106; bi,j is a various of ai,j; the outright worth of the contrast between numbers in any nearby pair of cells (two cells that share a similar side) in b is equivalent to k4 for some integer k≥1 (k isn't really something similar for all sets, it is own for each pair). We can show that the appropriate response consistently exists. Input The primary line contains two integers n and m (2≤n,m≤500). Every one of the accompanying n lines contains m integers. The j-th integer in the I-th line is ai,j (1≤ai,j≤16). Output The output ought to contain n lines each containing m integers. The j-th integer in the I-th line ought to be bi,j.Imagine a Turing machine M' that works like a normal Turing machine except that whenever it moves to the left, it moves by two squares instead of one. Its movements to the right are by one square as usual. Show that M' can compute all functions that normal Turing machines can compute.
- Computer Science Prove that the set M = {x ∈ R: x 2 = 2a3 b , a ∈ N, b ∈ N} is countably infinite. Your solution should either give a bijective function f : N → M or give pseudo-code of a program that prints all the values of such a function, in the following format (in this case you don’t have to define f explicitly, but need to also show the first five lines of output): 0: element of M 1: another element of M 2: yet another element of MPlease write Turing machine code that computes the function f(x) = 3x. Below is an example of some Turing machine code for reference on how the code should look. this does NOT mean that this is the correct way to start the code. this is just an example of the format I need. 1,B,R,2 2,1,R,2 2,B,1,3 3,1,L,3 Assuming x = 2, the starting tape should look like this: B|1|1|B and end up like thisB|1|1|1|1|1|1|B Or if x = 3, the starting tape should look like this:B|1|1|B and end up like thisB|1|1|1|1|1|1|1|1|1|B Please do not use chatgpt for this, it does not compute the correct answer I tried a million times. I keep getting answers from tutors here that are from chatgpt and it always ends up being incorrect for Turing machine code. Please feel free to check your answer with this Turing machine editor: https://amrits7.github.io/TuringMachineEditor/For a Turing machine M, (M) refers to the binary representation of M. For a Turing machine M, L(M) contains the set of all strings accepted by M. For a Turing machine M and an input x € {0,1}*, Steps(M, x) refers to the number of steps taken by M to execute on x before it halts. Here, one step of execution of M on x = one movement (left or right) of the tape head. For a Turing machine M and an input x = {0,1}*, we define the following: ReachCells(M,x) = {i : M reaches ith tape cell when M is executed on x} Informally, it contains all locations on the tape that are visited when M is ecuted on x. The leftmost location on the tape is the first tape cell, the location next to it is the second tape cell, and so on. A string w₁ is an anagram of w2 if w₁ can be obtained by rearranging the alphabets of w2. Formally, if w₁ is an n length string, wê is called an anagram of w₁ if there exists a permutation à on n elements such that π(w₁) = W2.