Ho: ? H:? v Determine if this test is left-tailed, right-tailed, or two-tailed. O two-tailed O left-tailed O right-tailed Should the standard normal (2) distribution or Student's (t) distribution be used for this test? O The standard normal (z) distribution should be used O The Student's t distribution should be used Determine the critical value(s) for this hypothesis test. Round the solution(s) to four decimal places. If more than one critical value exists, enter the solutions using a comma-separated list. Determine the test statistic. Round the solution to four decimal places. Determine the appropriate conclusion for this hypothesis test. O The sample data provide sufficient evidence to reject the null hypothesis that the average food delivery time from this company is 32.4 minutes or less and thus we conclude that average food delivery time is likely greater than 32.4 minutes. O The sample data do not provide sufficient evidence to reject the null hypothesis that the average food delivery time from this company is 32.4 minutes or less and thus we conclude that average food delivery time is likely 32.4 minutes or less, as advertised.
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- It takes an average of 12.4 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 69 injured patients to immediately tell the truth about the injury and noticed that they averaged 12.8 minutes for their blood to begin clotting after their injury. Their standard deviation was 1.94 minutes. What can be concluded at the the αα = 0.10 level of significance? For this study, we should use z-test for a population proportion or t-test for a population mean The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer = ≠ > < H1:H1: ? p μ Select an answer > = < ≠ The test statistic ? t or z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should: reject, accept, or fail to reject the null…It takes an average of 9.1 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 45 injured patients to immediately tell the truth about the injury and noticed that they averaged 9.1 minutes for their blood to begin clotting after their injury. Their standard deviation was 0.91 minutes. What can be concluded at the the αα = 0.10 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > < ≠ = H1:H1: ? μ p Select an answer = < ≠ > The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer accept fail to reject reject…It takes an average of 13.5 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 63 injured patients to immediately tell the truth about the injury and noticed that they averaged 13.6 minutes for their blood to begin clotting after their injury. Their standard deviation was 1.35 minutes. What can be concluded at the the αα = 0.10 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer ≠ = > < H1:H1: ? μ p Select an answer > ≠ = < The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer fail to reject accept…
- It takes an average of 14.8 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 47 injured patients to immediately tell the truth about the injury and noticed that they averaged 15.4 minutes for their blood to begin clotting after their injury. Their standard deviation was 1.48 minutes. What can be concluded at the the αα = 0.05 level of significance? The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer < ≠ > = H1:H1: ? μ p Select an answer < ≠ = > The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.)It takes an average of 14.5 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 65 injured patients to immediately tell the truth about the injury and noticed that they averaged 15.4 minutes for their blood to begin clotting after their injury. Their standard deviation was 3.05 minutes. What can be concluded at the the αα = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton mean is significantly greater than 14.5 at αα = 0.05, so there is statistically significant…It takes an average of 11.7 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will decline if the patient is immediately told the truth about the injury. The EMT randomly selected 50 injured patients to immediately tell the truth about the injury and noticed that they averaged 11.4 minutes for their blood to begin clotting after their injury. Their standard deviation was 1.47 minutes. What can be concluded at the the αα = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton mean is significantly less than 11.7 at αα = 0.05, so there is statistically significant…
- It takes an average of 10.5 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will change if the patient is immediately told the truth about the injury. The EMT randomly selected 40 injured patients to immediately tell the truth about the injury and noticed that they averaged 10.4 minutes for their blood to begin clotting after their injury. Their standard deviation was 2.55 minutes. What can be concluded at the the αα = 0.01 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton mean is significantly different from 10.5 at αα = 0.01, so there is statistically significant…It takes an average of 10.5 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will change if the patient is immediately told the truth about the injury. The EMT randomly selected 40 injured patients to immediately tell the truth about the injury and noticed that they averaged 10.4 minutes for their blood to begin clotting after their injury. Their standard deviation was 2.55 minutes. What can be concluded at the the αα = 0.01 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: Based on this, we should ___ the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton mean is significantly different from 10.5 at αα = 0.01, so there is statistically significant evidence to conclude that the population mean time for blood to begin clotting after an injury if the patient is told the truth immediately is different…It takes an average of 14.5 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will decline if the patient is immediately told the truth about the injury. The EMT randomly selected 50 injured patients to immediately tell the truth about the injury and noticed that they averaged 12.8 minutes for their blood to begin clotting after their injury. Their standard deviation was 4.35 minutes. What can be concluded at the the αα = 0.01 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer < > ≠ = H1:H1: ? μ p Select an answer ≠ > = < The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer accept fail to reject reject the…
- It takes an average of 10.8 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 46 injured patients to immediately tell the truth about the injury and noticed that they averaged 11.7 minutes for their blood to begin clotting after their injury. Their standard deviation was 2.98 minutes. What can be concluded at the the αα = 0.05 level of significance? The null and alternative hypotheses would be: Please provide number H0:H0: mean =Correct __?__ H1:H1: mean > Correct_ __?__ The test statistic t = __?__ (please show your answer to 3 decimal places.) The p-value = __?__ (Please show your answer to 4 decimal places.)To compare the dry braking distances from 30 to 0 miles per hour for two makes of automobiles, a safety engineer conducts braking tests for 35 models of Make A and 35 models of Make B. The mean braking distance for Make A is 43 feet. Assume the population standard deviation is 4.7 feet. The mean braking distance for Make B is 44feet. Assume the population standard deviation is 4.5 feet. At α=0.10, can the engineer support the claim that the mean braking distances are different for the two makes of automobiles? Assume the samples are random and independent, and the populations are normally distributed. Complete parts (a) through (e). a) identify the claim and state Ho and Ha b) find the critical values and identify the rejection regions c) Find the standardized test statistic z d) Decide whether to reject or fail to reject the null hypothesis. e) Interpret the decision in the context of the original claim.It takes an average of 11.2 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will change if the patient is immediately told the truth about the injury. The EMT randomly selected 40 injured patients to immediately tell the truth about the injury and noticed that they averaged 11 minutes for their blood to begin clotting after their injury. Their standard deviation was 3.02 minutes. What can be concluded at the the αα = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: p or u, <>= H1:H1: p or u, <,>,= The test statistic z or t is -0.419. Enter it here (please show your answer to 3 decimal places.) The p-value is 0.6776274622. Enter it here (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should rject, accept, or fail to reject the null hypothesis. Thus, the final conclusion…