î × ƒ = k‚ ƒ × k = î, k×î=j, A× B = -B × A, |Ã× B|= AB sin 0, FB = qv×B,H R = = mv ‚ FÅ = IL × B. qB Problem 1: A proton (q B = = +e = +1.60 × 10-19 C) moves through a uniform magnetic field given by (0.011 -0.02ĵ+ 0.03) T. At this instant the proton has a velocity given by v = v×î + vyĵ + (2000 m/sec)k and the magnetic force on the proton is F = (4.0 × 10¯¹7N)î + (2.0 × 10¯¹7 N)ĵ. What are v and vy? Answer: vx = -3500 m/sec and vy = 7000 m/sec.

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter22: Magnetic Forces And Magnetic Fields
Section: Chapter Questions
Problem 19P
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Question
î × ƒ = k‚ ƒ × k = î, k×î=j, A× B = -B × A, |Ã× B|= AB sin 0,
FB = qv×B,H R = =
mv
‚ FÅ = IL × B.
qB
Problem 1:
A proton (q
B
=
= +e = +1.60 × 10-19 C) moves through a uniform magnetic field given by
(0.011 -0.02ĵ+ 0.03) T. At this instant the proton has a velocity given by
v = v×î + vyĵ + (2000 m/sec)k and the magnetic force on the proton is
F = (4.0 × 10¯¹7N)î + (2.0 × 10¯¹7 N)ĵ. What are v and vy?
Answer: vx = -3500 m/sec and vy
=
7000 m/sec.
Transcribed Image Text:î × ƒ = k‚ ƒ × k = î, k×î=j, A× B = -B × A, |Ã× B|= AB sin 0, FB = qv×B,H R = = mv ‚ FÅ = IL × B. qB Problem 1: A proton (q B = = +e = +1.60 × 10-19 C) moves through a uniform magnetic field given by (0.011 -0.02ĵ+ 0.03) T. At this instant the proton has a velocity given by v = v×î + vyĵ + (2000 m/sec)k and the magnetic force on the proton is F = (4.0 × 10¯¹7N)î + (2.0 × 10¯¹7 N)ĵ. What are v and vy? Answer: vx = -3500 m/sec and vy = 7000 m/sec.
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