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If 13,736 = 1.3736 x 10^n, What is the value of n?
Please give the value for n
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- Use the References to access important values if needed for this question. Two-Step Algebra a =b+ cd lne In order to solve the equation above for d, you must: Step One Add the same expression to each side of the equation to leave the term that includes the variable by itself on the right-hand side of the expression: -b ta =-bv +b+ cd Ine Step Two Multiply both sides of the equation by the same expression: x(a - b) = xcd Ine The resulting equation is: d = SubmitQ1. The net potential energy between two adjacent ions, EN, is represented by A В E N pn where EN is the net energy in Joule (J), A and B are constants with values of 1.436 J.nm and 7.32 × 106 J.nm, r is the interatomic distance between the two ions in nanometer (nm), and n is a positive number with a value of 8.After sitting on a shelf for a while, a can of soda at a room temperature (69°F) is placed inside a refrigerator and slowly cools. The temperature of the refrigerator is 37°F. Newton's Law of Cooling explains that the temperature of the can of soda will decrease proportionally to the difference between the temperature of the can of soda and the temperature of the refrigerator, as given by the formula below: T = Ta + (To – Ta)e¬kt the temperature surrounding the object To = the initial temperature of the object t = the time in minutes the temperature of the object after t minutes k = decay constant T The can of soda reaches the temperature of 54°F after 40 minutes. Using this information, find the value of k, to the nearest thousandth. Use the resulting equation to determine the Fahrenheit temperature of the can of soda, to the nearest degree, after 95 minutes. Enter only the final temperature into the input box.
- Carry out each of the following calculations, paying special attention to significant figures, rounding, and units (J = joule, the SI unit of energy; mol = mole, the SI unit for amount of substance) (6.022 X 1 023 molecules/mol)( 1 .l 9 X 1 02 g) / 46.07 glmolSolid copper(II) chloride forms a hydrate of formula CuCl2 ⋅ xH2O. A student heated a sample of hydrated copper(II) chloride, in order to determine the value of x. The following results were obtained: mass of crucible = 16.221 g mass of crucible and hydrated copper(II) chloride = 18.360 g mass of crucible and anhydrous copper(II) chloride = 17.917 g At. Mass: Cu 63.55 Cl 35.45 H 1.008 O 16.00 1. Calculate the number of moles of anhydrous copper(II) chloride (answer must be expressed to 5 decimal places)Solid copper(II) chloride forms a hydrate of formula CuCl2 ⋅ xH2O. A student heated a sample of hydrated copper(II) chloride, in order to determine the value of x. The following results were obtained: mass of crucible = 16.221 g mass of crucible and hydrated copper(II) chloride = 18.360 g mass of crucible and anhydrous copper(II) chloride = 17.917 g At. Mass: Cu 63.55 Cl 35.45 H 1.008 O 16.00 1. Calculate the number of moles of H2O (answer must be expressed to 5 decimal places)
- Solid copper(II) chloride forms a hydrate of formula CuCl2 ⋅ xH2O. A student heated a sample of hydrated copper(II) chloride, in order to determine the value of x. The following results were obtained: mass of crucible = 16.221 g mass of crucible and hydrated copper(II) chloride = 18.360 g mass of crucible and anhydrous copper(II) chloride = 17.917 g At. Mass: Cu 63.55 Cl 35.45 H 1.008 O 16.00 1. Calculate percentage of H2O (answer must have 4 sig. fig)Solid copper(II) chloride forms a hydrate of formula CuCl2 ⋅ xH2O. A student heated a sample of hydrated copper(II) chloride, in order to determine the value of x. The following results were obtained: mass of crucible = 16.221 g mass of crucible and hydrated copper(II) chloride = 18.360 g mass of crucible and anhydrous copper(II) chloride = 17.917 g At. Mass: Cu 63.55 Cl 35.45 H 1.008 O 16.00 1. Calculate percentage of anhydrous copper(II) chloride (answer must have 4 sig. fig)A chemistry student needs 35.0g of acetone for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of acetone is ·0.790gcm−3 . Calculate the volume of acetone the student should pour out. Be sure your answer has the correct number of significant digits.
- Q1. The net potential energy between two adjacent ions, EN, is represented by A В EN pn where En is the net energy in Joule (J), A and B are constants with values of 1.436 J.m and 7.32 × 106 J.nm°, r is the interatomic distance between the two ions in nanometer (nm), and n is a positive number with a value of 8. Using these information, determine the equilibrium spacing between the two ions in nanometer (nm).A sample of nitrogen gas, N2, travels 17.0 cm in 4.5 minutes. How long in minutes would it take chlorine gas, Cl2, to travel a distance of 17.0 cm under the same conditions?Electrical energy is measured in kilowatt hours, kWH. A watt is 1 joule per second, a kilowatt is 1000 joules per second. An hour has 3600 seconds, therefore 1kWh=3.6x10^6 joules. How many kWh are there in a meal that is 437 Cal?
