If A = then det(A) Thus, -7 -91 3 A-1 -102 and det(A1) O is Nonzero 3 -34 34 [图] 3 7 -34 -102 x
If A = then det(A) Thus, -7 -91 3 A-1 -102 and det(A1) O is Nonzero 3 -34 34 [图] 3 7 -34 -102 x
ChapterP: Prerequisites
Section: Chapter Questions
Problem 3T
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Transcribed Image Text:an retry this question below
Find the area of a parallelogram with corner points at (1,2), (3,5), (8,5), and (6,2)
Area = 3
![If A =
then det(A)
Thus,
-7-9
-9 3
A-1
I -102
and det(A 1)
is Nonzero
3
-34
34
[림]
H
7
3
-34
-102
X
TO](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F18574973-f25e-4ab8-b7d6-6007b5b87fc4%2F69f21f38-97e4-4cbc-80ee-debf90fe495c%2F0ps00m_processed.jpeg&w=3840&q=75)
Transcribed Image Text:If A =
then det(A)
Thus,
-7-9
-9 3
A-1
I -102
and det(A 1)
is Nonzero
3
-34
34
[림]
H
7
3
-34
-102
X
TO
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