If load P = 22.1 kips, determine the normal force in bar (
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If load P = 22.1 kips, determine the normal force in bar (1).
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- Calculate Tension BD if P = 100 kN. 1m 2.5 m 250 N -1.5 m- 2 m 1.5 m- Use the editor to format your answerA ladder with a uniform cross-section has a length of 4.80-foot long. It weighs W Ib. It is arranged such that one end is on the ground and the other against a vertical wall. The angle of triction at all contact surtaces is 20 degrees. What is the value of the coefficient of triction? What is f, in terms of variable Na? What is the normal force at A in terms of variable W? Answer in three decimal placesStatics of Rigid Bodies (Round off to two (2) decimal places. Include negative sign (-) if the answer is negative.) The 13 kips force F acting on the simply supported beam. Determine the y component of F?
- Rope BCA passes through a pulley at point C and supports a crate at point A. Rope segment CD supports the pulley and is attached to an eye anchor embedded in a wall. Rope segment BC creates an angle of ø = 64.0 ° with the floor and rope segment CD creates an angle 0 with the horizontal. If both ropes BCA and CD can support a maximum tensile force Tmaz = 165 lb. what is the maximum weight Wmar of the crate that the system can support? What is the angle e required for equilibrium? Express your answers numerically in pounds and degrees to three significant figures separated by a comma. • View Available Hint(s) nν ΑΣφ vec Wmax.0 = lb, degreesThe beam-column is fixed to the floor and supports the load as shown in (Figure 1). Take F₁ = 7.5 kN, F₂ = 5 kN, and M=1.3 kN m. Follow the sign convention. Figure Part A NA = HA Value 0.6 m Determine the normal force at point A. Express your answer to three significant figures and include the appropriate units. Units 0.2m 2m 10.4 m ? 1 of 1Neglect the thickness of the bar. Take ua=ub=u suppose that b= 1 ft
- G H 930 150 800 200 Dimensions in millimeters The figure shown above is used for handicapped persons during a therapeutic treatment. A load of 930N is applied to the seat. Determine the following: a. Consider the 8, solve for the length of LBE and LBA (meters) b. Solve for the value of angles a and c. Solve for the force of: 1. Member FG 2. Pin H 3.Cylinder BA E 100 175 400 R LBE C 150 D 400 E 175 200 41⁰ B 900 1501,200 N-m 4,500 N-m 2,800 N-m 500 N-m (3) 0.70 m 1.80 m 0.70 m Complete the torsion diagram of rod ABCD loaded as shown by dragging the components and filling in the values. T (kNm) A D B 1700 4500 500 -1700 -1200 2800 1600 -2300 -4500 4000 2300 3300 -2800 -3300 1200 -500 -4000 -1600The cable carrying three 400-N loads has a sag at C of hC = 14 m. Calculate the following: 26.1 The magnitude of the tensile force in segment AB is Blank 1 N. 26.2 The magnitude of the tensile force in segment BC is Blank 2 N. 26.3 The magnitude of the tensile force in segment CD is Blank 3 N. 26.4 The magnitude of the tensile force in segment DE is Blank 4 N.
- Cable AB supports the uniformly distributed load of 4 kN/m. If the slope of the cable at A is zero, compute (a) the maximum tensile force in the cable; and (b) the length of the cable B 50 m 4 kN/m Tmax = 250 kN; S = 70 m Tmax = 300 kN; S = 75 m Tmax = 350 kN ; S = 80 m Tmax = 400 kN; S = 85 m 40 m A O OTDE= TBE Required information The structure consists of pin-connected members. Take X = 4 kN. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. = 2m Determine the force supported by all members. Enter forces as positive numbers if the member is in tension and as negative numbers if the member is in compression. (Round the final answers to four decimal places.) The force supported by all members are as follows: TAB -7.0711 KN TAD= -5 KN TBD= 2.2361 kN KN |1m-1m-1m-1m4 2 kN 3 KN X 3 KN D TEF= TBF= 4.4721 TCF= TBC= -5.6569 kN KN E KN KN F CThis arm is attached to a wall on the left. The right end is free hanging. Each section is 2.0m wide and 3.0m high. If the force at the end of the arm is F = 200.0N, what is the force in member 9? Use the Method of Sections. Use a positive number if it is in tension and a negative number if it is in compression.