If the material is a dry clay, which of the following is likely to weigh the least? one bank cubic yard one loose cubic yard one compacted cubic yard
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- Given a compacted aggregates with a size of 2", given the mass of aggregate plus measure equivalent to 10500g, mass of the measure is 350g and the factor of the measure is equivalent to 290 /cu. m. Calculate the Bulk density of the Sample? a. 35000 kg/m^3 b. 2903.5 kg/m^3 c. 2943.5 kg/m^3 d. 3270.07 kg/m^3Explain the concept behind why clay materials are naturally hydrophilic. Discuss their structure and its connection to this characteristic of clay.What is the term for the soil particle made of mostly quartz and feldspar?What is the term for the soil particle consisting of pieces of rocks with occasional particles of quartz, feldspar, and other minerals?
- Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = ½ ft³ Weight of empty bucket = 20.3 lb Weight of bucket filled with dry rodded coarse aggregate Trial 1 = 69.6 lb Trial 2 = 68.2 lb Trial 3 = 71.6 lb a. Calculate the average dry-rodded unit weight b. If the bulk dry specific gravity of the aggregate is 2.620, calculate the per- cent voids between aggregate particles for each trial.1. Calculate the following properties for the data provided in the Table below for a coarse aggregate sample. a. Bulk SSD specific gravity b. Bulk Dry specific gravity A Bulk Dry Sp. Gr. = c. Apparent specific gravity d. Absorption capacity. В — С B Bulk SSD Sp. Gr. = В — С where A Apparent Sp. Gr. = А — С A = dry weight B = SSD weight C = submerged weight В — А (100) A Absorption (%) Weight of Pan + Oven- Dry Aggregate Weight of Pan Weight of Submerged Aggregate Weight of Pan + SD Aggregate 0.8495 Ib 1.9885 lb 0.6870 lb 1.9630 Ib 2. If the Moisture Content of a stockpile sample of the same coarse aggregates is 1.85 %, what is the moisture state of aggregate sample? Select from the four standard moisture states. Explain how you arrived at the answer. 3. If Bulk unit weight of coarse aggerates is 98 Ib/ft³determine the % Voids of dry-rodded aggregate. Youlk S.G(Bulk Dry)*Pwater %Solids * 100 4. Determine the % solids for 2 cases discussed in pre-lab video by using below data.…Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained:Volume of bucket = 12 ft3Weight of empty bucket = 20.3 lbWeight of bucket filled with dry rodded coarse aggregate:Trial 1 = 76.6 lbTrial 2 = 75.1 lb Trial 3 = 78.8 lba. Calculate the average dry-rodded unit weightb. If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles for each trial.