If we know that the motion of the glider is constant acceleration motion, then there is a simple way to determine the value of the acceleration, because if it starts from rest, the motion follows the equation So: as long as we start the stopwatch at the moment the ribbon is cut, we can pick just one data point from the table above (the best choice is the one furthest away from t=0-can you see why that would be?) and use those values for d and t , plug into the equation above and solve for the acceleration.   Do this, find the acceleration and record that value below. Please also show the steps of your work (by typing in the equations) starting with the equation above, plugging in numbers, and solving for the numerical value for   As a check, this number should be 2 times the fit value for A from the last question of the previous part. If that's not (approximately) true, then it's a good place to review and/or consult your instructor.

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If we know that the motion of the glider is constant acceleration motion, then there is a simple way to determine the value of the acceleration, because if it starts from rest, the motion follows the equation

So: as long as we start the stopwatch at the moment the ribbon is cut, we can pick just one data point from the table above (the best choice is the one furthest away from t=0-can you see why that would be?) and use those values for d and t , plug into the equation above and solve for the acceleration.

 

Do this, find the acceleration and record that value below. Please also show the steps of your work (by typing in the equations) starting with the equation above, plugging in numbers, and solving for the numerical value for

 

As a check, this number should be 2 times the fit value for A from the last question of the previous part. If that's not (approximately) true, then it's a good place to review and/or consult your instructor.

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Transcribed Image Text:1 2 3 4 5 6 7 8 9 10 distance cm 1 4 10 15 25 35 45 58 75 92 d time S 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0
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