Implement the Boolean function F = xy + x’ y’ + y’z (a) With AND, OR, and inverter gates (b) With OR and inverter gates (c) With NOR and inverter gates
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Implement the Boolean function
F = xy + x’ y’ + y’z
(a) With AND, OR, and inverter gates (b) With OR and inverter gates (c) With NOR and inverter gates
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- With the following functions use a 4:1 multiplexer(mux) and minimum number of extra gates. Remember that to create the inverse of an input variable (i.e., A’, B’, etc.), you need to use an inverter. Hint:remember that you may need to try different variables on the select lines (i.e., A and B, or B and C, or A and C) to find the solution with the minimum number of extra gates. Implement each of the functions from from the above question using a 2:1 multiplexer(mux) and a minimumnumber of extra gates. Hint:remember that you may need to try different variables (i.e., A or B or C) on the select line to find the solutionwith the minimum number of extra gates. please explain in detail with a truth table as well as the schematics using a MUX.Exclusive OR (XOR) and Exclusive NOR (XNOR) gates can be used a. as parity generators b. as parity checkers c. as comparators d. as controlled inverters e. as all of the given answersStudy the circuit and determine the need for the 74LS04 inverters at the output of the XOR gates. What are the purposes of these inverters? 5W4 (LSB) DATA SW3 SWITCHES SW2 SWI FROM LOGIC SWITCH A A LSB B 6 13 2 UP A B C COUNT CLR FROM LOGIC 14 SWITCH B 21 4 91 10 12 74193 13 7 D 74L586 9+ 5V 74LS049 +5 V 3 15 142 D 16 31 DIBID ¹8 18 51 > I ill 9 L4 16 41 KS L3 L2 C Da +5V ܬܬܬܬ 14 Dala GND 16 +4 +4 14 12 4 +5V 1/2-74L$20 1/6-74LS04 --- 10 DC VOLTMETER V
- Q4: Given the table below that shows the tcp and tpp for each of the logic gate in the circuit below. Please compute tcp and tpp for the whole circuit? T3 C F1 T2 T4 F2 tcD tPD Inverter 0.1 ns 0.6 ns AND 0.4 ns 0.8 ns XOR 0.5 ns 1.8 ns OR 0.4 ns 0.9 nsimplement the following boolean function with OR and inverter gates F = xy' + x'y + y'z4. Construct a combinatorial circuit using inverters, OR gates, and AND gates that produce the output (~pA~q) A (~ (p V r)) from the input bits p, q, and r.
- Question 6 To implement the following expression as it is stated it takes X = ABC + CD + C'A' + AD' +A'BE %3D O five AND gates, one OR gate, and no inverters O five OR gates, one AND gate, and four inverters O five AND gates, one OR gate, and four inverters O five AND gates, three OR gates, and three invertersProblem #2: Consider the given design below: A D₂ B D₁ C-Do m7 m6 m5 3-to-8 m4 Decoder m3 m₂ m₁ mo F 1. Re-implement function F(A,B,C) using the minimum number of 4-to-1 MUX. Other gates (inverter, OR, etc) are not allowed. Complemented inputs (A’, B', C') are also not allowed, and will have to be implemented using MUX.Disscussion 1- In OR gate table why 1+ 1 = 1? 2- Explain the basic logic gates, complete three and four input logic gates truth table.. 3- What is the purpose of a truth table and algebraic function? 4-What is the purpose of an inverter in a digital circuit? -5- When is the output of an OR gate HIGH? -6- When is the output of an OR gate LOW? 7- Describe the truth table for a 3-input OR gate.
- Draw a circuit to realize each of the following expressions using AND gates, OR gates, and inverters: a. F=A+ B ¯ C, b. F=A B ¯ C+AB C ¯ + A ¯ BC, c. F = ( A ¯ + B ¯ +C)(A+B+ C ¯ ) (A+ B ¯ +C)Simplify the following Boolean Function using K-map: F(a, b, c) = E(0,1,5,6,7) and implement the above function (a) With logic gates (AND, OR, Inverters) (b) With NAND gates (c) With NOR gatesa) Create a 4 Variable Karnaugh Map in paper by mapping 1’s for given standard SOP Boolean expression. After mapping , make relevant groups within Karnaugh Map by considering rules for making groups for 4 variable Karnaugh Map. After making relevant grouping , extract the minimum SOP expression by considering rules for extracting minimum SOP using Karnaugh Map. * Standard SOP: *Create Circuit Diagram using logic gates and logic converter in Multisim for given standard SOP and minimum SOP which you have solved. Do make sure that truth table for both expressions should evaluate same result.