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In §12.2 Lamport's Hash we mentioned the notion of using only 64 bits of the hash. At each stage, 128 bits are computed, 64 bits are thrown away, and the hash of the retained 64 bits is used in the next stage. The purpose of only using 64 bits is so that a human does not need to type as long a string. Assuming the person will still only type 64 bits, does it work if hashn does a hash of all 128 bits of hashn-1, but what the person actually transmits is 64 bits of the result?

In §12.2 Lamport's Hash we mentioned the notion of using only 64 bits of the hash. At each stage, 128 bits are computed, 64 bits are thrown away, and the hash of the retained 64 bits is used in the next stage. The purpose of only using 64 bits is so that a human does not need to type as long a string. Assuming the person will still only type 64 bits, does it work if hashn does a hash of all 128 bits of hashn-1, but what the person actually transmits is 64 bits of the result?

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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In §12.2 Lamport's Hash we mentioned the notion of using only 64 bits of the hash. At each stage, 128 bits are computed, 64 bits are thrown away, and the hash of the retained 64 bits is used in the next stage. The purpose of only using 64 bits is so that a human does not need to type as long a string. Assuming the person will still only type 64 bits, does it work if hashn does a hash of all 128 bits of hashn-1, but what the person actually transmits is 64 bits of the result?

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