Vin =20 mV,1 kHzPP+294 kHz256 kHz265 kHz244 kHz218 kHzV outR• 82 ΚΩwwwwwwER* 10 ΚΩ20 mV1 kHzPPR₁w22 ΚΩ(a)(b)Both op-amps have AOL = 100 dB and f₁ = 2 MHz.Refer to Figure (b). The closed loop bandwidth, fc(cl), is+R150 ΚΩV₁out

The given inverting amplifier is shown below: The closed-loop voltage gain of the above inverting…

in 20 mV, 1 kHz PP wwwwww 294 kHz 256 kHz 265 kHz 244 kHz 218 kHz out R • 82 ΚΩ ER * 10 ΚΩ Vin= 20 mV 1 kHz PP R₁ w 22 ΚΩ (b) Both op-amps have AOL = 100 dB and f = 2 MHz. Refer to Figure (b). The closed loop bandwidth, fc(cl), is + R₁ 150 ΚΩ V out

in 20 mV, 1 kHz PP wwwwww 294 kHz 256 kHz 265 kHz 244 kHz 218 kHz out R • 82 ΚΩ ER * 10 ΚΩ Vin= 20 mV 1 kHz PP R₁ w 22 ΚΩ (b) Both op-amps have AOL = 100 dB and f = 2 MHz. Refer to Figure (b). The closed loop bandwidth, fc(cl), is + R₁ 150 ΚΩ V out

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

Vin =
20 mV,
1 kHz
PP
+
294 kHz
256 kHz
265 kHz
244 kHz
218 kHz
V out
R
• 82 ΚΩ
wwwwww
ER
* 10 ΚΩ
20 mV
1 kHz
PP
R₁
w
22 ΚΩ
(a)
(b)
Both op-amps have AOL = 100 dB and f₁ = 2 MHz.
Refer to Figure (b). The closed loop bandwidth, fc(cl), is
+
R
150 ΚΩ
V₁
out

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