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In a cross between a homozygous red-eyed female fruit fly and a white-eyed male fruit fly, what is the expected outcome
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- A male fruit fly, heterozygous for both vestigial wings and ebony body, is crossed with a female homozygous for normal wings and heterozygous for ebony body. What fraction of their offspring will have normal wings and an ebony body?In fruit flies, L= long wings and l = short wings. When a long-winged fly is crossed with a short winged fly, the offspring exhibit a 1:1 ratio. What is the genotype of the parental flies?In Drosophila, ebony body colour is produced by a recessive gene a and wild-type (gray) body colour by its dominant allele a+. Vestigial wings are governed by a recessive gene vg, and normal wing size (wild type) by its dominant allele vg+. If wild-type dihybrid flies are crossed and produce 256 progeny, how many of these progeny flies are expected in each phenotypic class?
- In a trihybrid cross of a tall, purple-flowered pea plant with round seeds (TtPpRr) with a tall, white-flowered pea plant with wrinkled seeds (Ttpprr). Determine the probability of each offspring that will be produced.What phenotypic proportions would be expected if the genes for red eyes and for white-banded wings were located on different chromosomes?In currant moths, their Light color is sex-linked and recessive (d) to dark color (D). Question: What are the genotype and the phenotype of the parents if a certain cross yields ½ dark and ½ light colored females and all dark males? Take note that female moths are heterogametic.
- A true breeding male fly with eosin eyes (CCXw-eY) is crossed to a red-eyed female who is heterozygous for both the cream (C) and eosin eyes (Xw-e) allele. What will be the phenotypic ratio of their offspring?The probability that both alleles in the offspring are type A is the product of the probability that the allele from the pollen is A and the probability that the allele from the ovule is A (we will derive this in Section 6.5). What is the probability that the offspring of a homozygous parent is homozygous? What is the probability that the offspring of a homozygous parent is heterozygous?PURPLE VESTIGIAL DIHYBRID CROSS In the parental generation, you mate a pure-breeding wild-type female (put/pu+;vg+/vg+) with a pure-breeding purple, vestigial (pu/pu;vg/vg) to produce an F1 generation that is all wild-type (pu*/pu;vg+/vg). Note that the F1 flies are all dihybrid. Next, you mate several F1 dihybrid females (pu*/pu;vg+/vg) with tester males, which are purple, vestigial (pu/pu;vg/vg). The offspring of this dihybrid testcross are: Phenotype Genotype Tester Gamete Dihybrid Gamete Number Wild-type 437 417 77 59 Purple, vestigial Vestigial Purple Copy the table into your notes and derive the dihybrid gametes following the example in the first section. The columns in blue (phenotypes and numbers of offspring) are what you can see and count. The genotypes of the testcross offspring (orange) must be deduced from the phenotypes and knowing that the tester contributed pu vg gametes. Finally, you can deduce the dihybrid gametes (green) by subtracting the tester gamete contribution…
- What are the F1 phenotypes expected from a cross between a heterozygous red-eyed female fruit fly (XWXw) and a hemizygous red-eyed male fruit fly (XWY)? half of the F1 males will have white eyes, and all F1 females will have red eyes half of the F1 females will have white eyes, and half of the F1 males will have red eyes all F1 males will have white eyes, and all F1 females will have red eyes all F1 males will have white eyes, and all F1 females will have white eyes all F1 progeny will have red eyesButterflies have an X-Y sex-determination system that is different from that of flies or humans. Female butterflies may be either XY or X0, while butterflies with two or more X chromosomes are males. This photograph shows a tiger swallowtail gynandromorph, which is half male (left side) and half female (right side). Given that the first division of the zygote divides the embryo into the future right and left halves of the butterfly, propose a hypothesis that explains how nondisjunction during the first mitosis might have produced this unusual-looking butterfly. Question is also in the picture.In Drosophila, gray body color is dominant to ebony body color, while long wings are dominant to vestigial wings. Assuming that the P1 individuals are homozygous, work the following crosses through the F2 generation, and determine the genotypic and phenotypic ratios for each generation. (a) gray, long x ebony, vestigial